The trig functions that you need to deal with are
Sine
Cosine
Tangent
Cotangent
Cosecant
Secant
You need to write a single expression using all six trig functions such that the value of the expression equals 3.
To make this as simple as possible, the first thing I would do is look up the values of these functions and identify which ones are equal to either 1/2 or 1.0 or 2.0
sin(30º) = 1/2
sin(90º) = 1
cos(0º) = 1
cos(60º) = 1/2
tan(45º) = 1
csc(30º) = 2
csc(90º) = 1
sec(0º) = 1
sec(60º) = 2
cot(45º) = 1
If we only had to use three trig functions (sin, cos, tan), one possibility is
tan(45º) + cos(0º)/sin(30º) = 1 + 1/(1/2) = 1 + 2 = 3
noticed how I chose one each of the required functions and the operations so that the result = 3.
Now it is up to you to figure out how to combine all six trig functions so that they equal zero. There are many possibilities for you to choose from..
Step-by-step explanation:
< AEB + < BEC = 180° {BEING LINEAR PAIR }
26° + < BEC = 180°
< BEC = 180° - 26°
< BEC = 154°
ARC BC = < BEC ( relation between arc and central angle)
Arc BC = 154°
Hope it will help :)
Answer:
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Step-by-step explanation:
i think so but it will help you
Answer:0.004 is the probability that the mean salary of the sample is less than $57,500.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = $60,500
Standard Deviation, σ = $6,400
Sample size, n = 32
#if you need any queshtions answered within secs/mins hit me up and I got you!
Answer:
Step-by-step explanation:
The relevant relations here are ...
- the sum of arc measures in a semicircle is 180°
- the sum of angles in a triangle is 180°
<h3>Arc measures</h3>
The given arc CD is part of the semicircular arc CDA. The remaining arc, DA, is the supplement of CD:
arc DA = 180° -CD = 180° -125° = 55°
Central angle AOD has the same measure, 55°. That is one of the acute angles in right triangle AOB, so the other one is the complement of 55°.
∠ABO = 90° -∠AOB = 90° -55°
∠ABO = 35°
<h3>Triangle angles</h3>
In right triangle ABC, angle ABC is given as 55°. The other acute angle, ACB, will be the complement of this.
∠ACB = 90° -∠ABC = 90° -55°
∠ACB = 35°
In the figure, angles ABO and ACB have measures of 35°.
