A consumer organization estimates that over a 1-year period 20% of cars will need to be repaired once, 8% will need repairs
1 answer:
Answer:
Probability that a car need to be repaired once = 20% = 0.20
Probability that a car need to be repaired twice = 8% = 0.08
Probability that a car need to be repaired three or more = 2% = 0.02
a) If you own two cars what is the probability that neither will need repair?
Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3
Probability that car need no repair = 1-0.3=0.7
Neither car will need repair=
b) both will need repair?
Probability both will need repair =
c)at least one car will need repair
Neither car will need repair=
Probability that at least one car will need repair= 1-0.49 = 0.51
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Answer:
8 Roses; 1 lilie ; 3 irises
Step-by-step explanation:
Let the number of roses be 'a' , number lilies be 'b' and number of irises be 'c'
$300 for 10 centerpieces means $30 per centerpiece. therefore,
.......................(1)
also each centerpiece must contain 12 flowers, therefore,
.................................(2)
also twice as much roses as the number of irises and lilies combined
............................... (3)
a) System of equation are equations (1) , (2) & (3).
Writing a matrix equation
b) Solving the simultaneous equation,
from (3),
substituting for 'a' in equation (1) and (2),
⇒ 2.5(2b+2c)+4b+2c=30
⇒ 5b + 5c + 4b + 2c = 30
⇒ 9b + 7c = 30 ..................... (4)
⇒ 2b + 2c + b + c = 12
⇒ 3b + 3c = 12
⇒ b = 4 - c ..............................(5)
Substituting (5) in (4)
9 (4 - c) + 7c = 30
36 - 9c+7c =30
36-30 = 2c
c = 3
b = 4-3 = 1
a = 2(3+1) = 8