12. 4(s+5)
4s+20
15. 2(3r-12)
6r-24
18. -3(16-3d)
9d-48
Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer: 6.2
Step-by-step explanation: 3.1 = x/2
x/2=3.1
x/2(2)=3.1(2)
x=6.2