Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
volume cylinder
=3.14×3^2×5
=141.3 cubic inches
volume sphere
=4/3×3.14×3^3
=113.04 cubic inches
difference between volume of cylinder and sphere
=141.3-113.04
=28.26 cubic inches
Just quit school bro it’s not worth it
Shaded circles = 4
Total circles = 12
=
as a simplified expression =
We can simplify it even more =
Fraction =
Equivalent decimal = 1 ÷ 3 = 0.33
