What is the inverse function of -5 (x-4) ^2+80

1 answer:

8 0

F(x)=-5(x-4)^2+80
f(x)=-5(x²-8x+16)+80
f(x)=-5x²+40x-80+80
f(x)=-5x²+40x

Replace f(x) to y, now switch the location of the variables x and y. Solve for new y.

y=-5x²+40x
x=-5y²+40y
0=-5y²+40y-x

Use quadratic formula to find the value of y.

y=-40+-√(40^2 -4(-5)(-x)/2(-5)
f^-1(x)= (-40+-√1600-20x)/-10 <--- Not too sure about this one :/

Hope I helped :)

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