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Hitman42 [59]
3 years ago
11

Inverse of f(x) = 4x+16

Mathematics
1 answer:
vodomira [7]3 years ago
5 0
F-1 (X)= x/4 -4 I think this is it
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tangare [24]

Heylo! :D

How are ya? :)

4 0
3 years ago
Diego had $21.32 and gave $9.50 to Elena. How much did he have left?
Charra [1.4K]

Answer:

11.82

Step-by-step explanation: I know this because 21.32-9.50= 11.82

7 0
3 years ago
3-5b=-32<br><br> Please help!
Inessa05 [86]

Answer:

b=7

Step-by-step explanation:

3-5b=-32

-5b=-32-3

-5b=-35

Divide both sides by -5

b=7

7 0
3 years ago
Read 2 more answers
Hi. Please I need help with these questions.
ElenaW [278]

Answer:

Q 12 roots of the equation

2x^{2} -6+1=0 \\= (x-\frac{\sqrt{10} }{2})(x+\frac{\sqrt{10} }{2})\\

∝ = \frac{\sqrt{10} }{2}

β = -\frac{\sqrt{10} }{2}

no matter if u oppose the root

(i) 2(\frac{\sqrt{10} }{2})(-\frac{\sqrt{10} }{2} )^{2}+2(\frac{\sqrt{10} }{2} )^{2}(-\frac{\sqrt{10} }{2})+2(

(ii)((\frac{\sqrt{10} }{2})^{2} - 3 (\frac{\sqrt{10} }{2})(-\frac{\sqrt{10} }{2}) + ((-\frac{\sqrt{10} }{2})^{2}) = \frac{25}{2}

Q 13  roots of equation

4x^{2} -3x-4=0\\\alpha = -0.693\\\beta = 1.443

the roots of the second equation are

x1 = 1/3(-0.693) = -0.231

x2 = 1/3(1.443) = 0.481

the equation is

(x+0.231)(x-0.481)=0

x^{2}-\frac{1}{4} x-\frac{1}{9}

4 0
3 years ago
A political candidate has asked you to conduct a poll to determine what percentage of people support him. If the candidate only
Nadusha1986 [10]

Answer:

The sample size required is, <em>n</em> = 502.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p\cdot (1-\hat p)}{n}}

The margin of error is:

MOE=z_{\alpha/2}\sqrt{\frac{\hat p\ \cdot (1-\hat p)}{n}}

Assume that 50% of the people would support this political candidate.

The margin of error is, MOE = 0.05.

The critical value of <em>z</em> for 97.5% confidence level is:

<em>z</em> = 2.24

Compute the sample size as follows:

MOE=z_{\alpha/2}\sqrt{\frac{\hat p\ \cdot (1-\hat p)}{n}}

       n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)}}{MOE}]^{2}

           =[\frac{2.24\times \sqrt{0.50(1-0.50)}}{0.05}]^{2}\\\\=501.76\\\\\approx 502

Thus, the sample size required is, <em>n</em> = 502.

4 0
3 years ago
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