All categories

3 years ago

I need help with both of these plss

Mathematics

1 answer:

oksian1 [2.3K]3 years ago

5 0

Answer:

3. All you did was switch the numbers, so it will still equal the same :)

4. 8a and the other 8a cancel each other out, so since 8 has no variables, it ends up by itself.

You might be interested in

A batter hits a baseball into the air

azamat

The answer is h(5) = 75.

Where x=5, y=75

4 0

3 years ago

Read 2 more answers

I seriously need help

777dan777 [17]

Answer:

x(t) = - 5 + 6t and y(t) = 3 - 9t

Step-by-step explanation:

We have to identify the set of parametric equations over the interval 0 ≤ t ≤ 1 defines the line segment with initial point (-5,3) and terminal point (1,-6).

Now, put t = 0 in the sets of parametric equations in the options so that the x value is - 5 and the y-value is 3.

x(t) = - 5 + t and y(t) = 3 - 6t and

x(t) = - 5 + 6t and y(t) = 3 - 9t

Both of the above sets of equations satisfy this above conditions.

Now, put t = 1 in both the above sets of parametric equations and check where we get x = 1 and y = -6.

So, the only set, x(t) = - 5 + 6t and y(t) = 3 - 9t satisfies this condition.

Therefore, this is the answer. (Answer)

8 0

3 years ago

Find DC (Image Below)

ioda

Answer:

79239729379249

Step-by-step explanation:

your aswer is 284389300 oo

6 0

3 years ago

Find dy/dx if y =x^3+5x+2/x²-1

stiks02 [169]

<u>Differentiate using the Quotient Rule</u> –

$\qquad$ $\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\$

According to the given question, we have –

f(x) = x^3+5x+2
g(x) = x^2-1

Let's solve it!

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2) \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5) - ( x^3+5x+2) 2x}{(x^2-1)^2 }\\$

$\qquad$ $\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\$

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\$

$\qquad$ $\pink{\therefore \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}} = \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\$

7 0

2 years ago

Ryans living room is 10 feet wide, 12 feet long, and 10 feet high. If one gallon of paint covers 400 square feet of surface area

Delicious77 [7]

We have to calculate the suface of the four walls and the ceiling.
Surface of the four walls=2(10 ft * 10ft ) + 2(12 ft * 10 ft)=200 ft² + 240 ft²=
=440 ft²
Surface of the ceiling=10 ft * 12 ft=120 ft²

Total surface=440 ft² + 120 ft²=560 ft²

Now, we have to caluclate the number of gallons of paint.

1 gallon------------------------400 ft²
x----------------------------------560 ft²

x=(1 gallon * 560 ft²) / 400 ft²=1.4 gallons.

answer: Ryan need to paint all four walls and the ceiling 1.4 gallons.

6 0

3 years ago