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3 years ago

8

If yall needs to talk or get points (20) come here

2 answers:

Aneli [31]3 years ago

4 0

Answer:

thanks

Step-by-step explanation:

nadezda [96]3 years ago

4 0

Answer:

umm sure why not

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Write 25/100 in simplist form

gizmo_the_mogwai [7]

1/4 is 25/100 in simplest form.
Tell me if this helps!!!

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3 years ago

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Solve 8[7-(6x-6)]+6x=0

bazaltina [42]

8[7 - (6x - 6)] + 6x = 0

8[7 - 6x + 6] + 6x = 0

56 - 48x + 48 + 6x = 0

104 - 42x = 0 .

- 42x = - 104 .

x = 52 / 21

x ≈ 2.476

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3 years ago

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If P = (5,4), find the image of P under the following rotation. 90° counterclockwise about the origin ([?], [ ])

ANTONII [103]

Answer: (-4,5)

Step-by-step explanation:

Rotating 90 deg. counterclockwise maps (x,y) onto (-y,x), so (5,4) maps onto (-4,5).

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2 years ago

Emma sold 18 cups of lemonade in 4 hours. The next day was warmer and she sold twice as much lemonade in the same amount of time

Gre4nikov [31]

That would be (2)(18 cups) / (4 hours), or 9 cups per hour.

3 0

3 years ago

Learning Task 3:

padilas [110]

Answer:

$Area = x^2- 25$

$Area =9x^2 +24x + 16$

$Length = (3x -2)$

$Speed = \left(y^2-3y+1\right)$

$Product = 3m^3 + 6m^2 - 6m$

Step-by-step explanation:

Solving (1):

$Length = (x + 5)$

$Width = (x - 5)$

Required

Calculate Area

$Area = Length * Width$

$Area = (x + 5) * (x - 5)$

$Area = x^2 + 5x - 5x - 25$

$Area = x^2- 25$

Solving (2):

Given

$Length = (3x + 4)$

Required: Calculate Area

$Area =Length * Length$

$Area =(3x + 4) * (3x + 4)$

$Area =9x^2 + 12x + 12x + 16$

$Area =9x^2 +24x + 16$

Solving (3):

$Area = 3x^2 + 7x - 6$

$Width = x + 3$

Required: Calculate Length

$Area = Length * Width$

$Length = \frac{Area}{Width}$

$Length = \frac{3x^2 + 7x - 6}{x + 3}$

Factorize the numerator

$Length = \frac{3x^2 + 9x -2x - 6}{x + 3}$

$Length = \frac{3x(x + 3) -2(x + 3)}{x + 3}$

$Length = \frac{(3x -2) (x + 3)}{x + 3}$

Divide by x + 3

$Length = (3x -2)$

Solving (4):

$Distance = (2y^3 - 7y^2 + 5y -1)$

$Time = 2y - 1$

Required: Determine the average speed

This is calculated as:

$Speed = \frac{Distance}{Time}$

$Speed = \frac{2y^3 - 7y^2 + 5y -1}{2y - 1}$

Factorize the numerator

$Speed = \frac{\left(2y-1\right)\left(y^2-3y+1\right)}{2y - 1}$

$Speed = \left(y^2-3y+1\right)$

Solving (5):

Multiply $(m^2 + 2m - 2)$ by sum of $(m + 3)$ and $(2m - 3)$

First, calculate the sum:

$Sum = m + 3 + 2m - 3$

$Sum = m + 2m+3 - 3$

$Sum = 3m$

Then, the product

$Product = (m^2 + 2m - 2)(3m)$

$Product = 3m^3 + 6m^2 - 6m$

6 0

3 years ago

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