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3 years ago

Ive never been good with these kind of questions

Mathematics

1 answer:

bearhunter [10]3 years ago

8 0

Answer:

The answer to your question is Equation y = -4x - 6 Slope -4

Point = (1 , -5)

Step-by-step explanation:

Data

Point = (1 , -5)

Process

1.- Get another point from the line

-This point is B = (0, -1)

2.- Get the slope of the line

Formula

m = (y2 - y1) / (x2 - x1)

x1 = 1 y1 = -5 x2 = 0 y2 = -1

-Substitution

m = (-1 + 5) / (0 - 1)

-Simplification

m = 4/-1

-Result

m = -4

3.- Find the equation of the line

Formula

y - y1 = m(x - x1)

-Substitution

y + 5 = -4(x - 1)

-Simplification

y + 5 = -4x - 1

-Solve for y

y = -4x - 1 - 5

-Result

y = -4x - 6

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Find the limit

Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

On substituting directly x = 1, we get,

$\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}$

$\rm \: = \sf \: \: - \infty \: - \: \infty$

which is indeterminant form.

Consider again,

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

can be rewritten as

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]$

$\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}$

$\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}$

$\rm \: = \: \sf \boxed{2}$

Hence,

$\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}$

$\rule{190pt}{2pt}$

7 0

2 years ago

Read 2 more answers

Solve the following systems of equations 2a+4b+c=5 ; a-4b=-6 ; 2b+c=7.

SOVA2 [1]

Answer:

a = -2

b = 1

c = 5

Step-by-step explanation:

Given:

2a + 4b + c = 5 ............(1)

a - 4b = - 6

a = 4b - 6 .............(2)

2b + c = 7

c = 7 - 2b ...........(3)

substituting 2 and 3 in 1, we get

2(4b - 6 ) + 4b + (7 - 2b) = 5

8b - 12 + 4b + 7 - 2b = 5

10b - 5 = 5

b = 1

substituting b in 2, we get

a = 4(1) - 6

a = -2

substituting b in 3, we get

c = 7 - 2(1)

c = 5

thus,

a = -2

b = 1

c = 5

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3 years ago

Sorry this is the last one! Help for brainliest answer

laila [671]

Answer:

5, 6, 9, 15

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2 years ago

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What is the value of the expression 9 × 2 + 2 × 5²

NARA [144]

$9 \times 2 + 2 \times {5}^{2} \\ = 18 + 2 \times 25 \\ = 18 + 50 \\ = 68$

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2 years ago

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Please show work and be done soon

stich3 [128]

9514 1404 393

Answer:

x = 22.5°

Step-by-step explanation:

Angle BED ≅ angle EBC = 6x, so angle BEA = 4x. The angles FEB and BEA form a linear pair, so we have ...

4x +4x = 180°

x = 22.5° . . . . . . divide by 8

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BED and EBC are "alternate interior angles" with respect to transversal BE crossing parallel lines DE and AC.

8 0

2 years ago