Only selections B and D give a maximum height of 13 at t=3. However, both of those functions have the height be -5 at t=0, meaning the ball was served from 5 ft below ground. This does not seem like an appropriate model.
We suspect ...
• the "correct" answers are probably B and D
• whoever wrote the problem wasn't paying attention.
Answer:
I missed the part where that's my problem
35
Area of rectangle
21m^2
Area of one triangle
divide length of 7 by 2 (3.5)
gives you length b (unknown side that is not hypotenuse)
then multiply by width of triangle (4)
3.5 * 4 = 14
and in this situation there is no need to divide by two, because you essentially have one full square from both the triangles. this only works when both triangles are the same.
add the area of the rectangle
14+21= 35
35m^2
Answer:
the smallest possible perimeter is 6
Step-by-step explanation:
since the smallest possible prime number is 2 it would make since if each side is 2 which makes the smallest perimeter possible. i really hope this helped :)
Answer:
<em>Answer</em><em> </em><em>is</em><em> </em><em>16x</em><em>^</em><em>4</em>
Step-by-step explanation:
<em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>
