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shepuryov [24]
3 years ago
11

2.) Priya is stacking building blocks to make a tower. She takes a break

Mathematics
2 answers:
ahrayia [7]3 years ago
5 0

Answer:

4 feet

Step-by-step explanation:

Marizza181 [45]3 years ago
3 0
5/8x? =2 1/2
And
5/8 - 2 1/2 =?
The answer would be those 2 can you plz park this a bran list
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The musical “Rent” boasts there are 525,600 minutes in a year. Verify that this is correct for a 365-day (non-leap year) year.
galben [10]

Answer:

Verified

Step-by-step explanation:

minutes to hours:

525600/60

8760

hours to days:

8760/24

365

so there are 525600 minutes in 365 days. Confirmed

4 0
3 years ago
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20 POINTS MARKING BRAINLEIST IF QUICK AND RIGHT
RoseWind [281]

Answer/Step-by-step explanation:

[D]

Polynomials will be closed under an operation if the operation produces another polynomial. When multiplying polynomials, the variables' exponents are added, according to the rules of exponents.

(Note: exponents in polynomials are whole numbers.)

 

[RevyBreeze]

4 0
3 years ago
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Find the following of each arc measure
Dimas [21]
ZW= 108
VW= 55
UY= 34
8 0
3 years ago
When you can.. please answer these! THANK YOU SO MUCH WAHHH
rodikova [14]

Answer:

1-C

2-F

3-A

4-D

5-B

6-E

Step-by-step explanation:

4 0
3 years ago
Find the center vertices and foci of the ellipse with equation 2x^3+8y^2=16
netineya [11]

Answer:

Step-by-step explanation:

First of all, you have a typo. But that's ok, we can work around it. The equation NOT yet in standard form for an ellipse should be:

2x^2+8y^2=16

Putting it into standard form requires that the right side of the equation equals 1. That means that we need to divide everything by 16 to accomplish that. When we do that, we will get the standard form:

\frac{x^2}{8}+\frac{y^2}{2}=1

The general form is either

\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1 or

\frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1

where a is ALWAYS bigger than b. So if the bigger denominator is under the x numerator, this is an ellipse that is elongated horizontally. If the larger denominator is under the y numerator, then this is an ellipse that is elongated vertically. As you can see from our standard ellipse equation, the 8 is under the x numerator, so this is a horizontally elongated ellipse.

If a^2=8, then a=\sqrt{8} which is approximately 2.83 units.

If b^2=2, then b=\sqrt{2} which is approximately 1.41 units.

Since the ellipse is elongated horizontally, the a value starts at the center of the ellipse and goes 2.83 units to the right and left of the center; the b value starts at the center of the ellipse and goes 1.41 units both up and down from the center. But what's the center?

In the standard form above involving the h and the k in the numerators, the h and k indicate the coordinates of the center. h is like the x coordinate and k is like the y coordinate. Since our ellipse does not have c^2=8-2a constant in a set of parenthesis for either the x or the y term, the center is at (0, 0). From the center then, we go go both right and left to (2.83, 0) and (-2.83, 0) for the vertices of the ellipse. The co-vertices would be (0, 1.41) and (0, -1.41).

The foci have the formula (h + c, k) for the focal point to the right of the center and (h - c, k) for the focal point to the left of the center. But how do we find c?

c^2=a^2-b^2

We already know that a^2=8 and b^2=2, so

c^2=8-2 and

c=\sqrt{6}

That means that the foci have the coordinates (\sqrt{6},0) and (-\sqrt{6},0)

and you're done!!

8 0
3 years ago
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