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3 years ago

Please help with my geometry

Mathematics

1 answer:

faust18 [17]3 years ago

5 0

Answer:

www.mahtpapa.com

Step-by-step explanation:

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There were several sunny days this year before my birthday. Since my birthday, there have been 171717 more sunny days. My birthd

Lesechka [4]

Answer:

66 sunny days before birthday

Step-by-step explanation:

Total sunny days after birthday = 17

Total sunny days in year = 83

Birthday was not sunny

Total sunny days before birthday = 83 -17

= 66 sunny days

Read more on Brainly.in - https://brainly.in/question/6937259#readmore

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4 years ago

How many 30 angles does it take to make a full turn

steposvetlana [31]

12. A full turn is 360 degrees. 360 divided by 30 is 12.

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3 years ago

Read 2 more answers

What are exponential functions

Degger [83]

Answer:

A function with a positive constant other than 1 raised to a variable exponent.

Step-by-step explanation:

7 0

3 years ago

6. A bookstore recorded a decrease in the sales of paperback books over the past year. From last year to this year the store exp

tensa zangetsu [6.8K]

Answer:

6966

Step-by-step explanation:

7740*10%=774

7740-774=6966

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3 years ago

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$

$= \int\limits343 cos^{2} \theta \, d\theta$

8 0

4 years ago