Answer:
Srue what's your question
Step-by-step explanation:
The function
f(x) is even
g(x) is neither even nor odd
h(x) is odd
Steps:
for an even function it holds that f(-x) = f(x):
f(-x) = (-1)^6 x^6 - (-1)^4 x^ 4 = x^6 - x^4 = f(x) => f is even
for an odd h(x) it holds that h(-x) = -h(x):

It is easy to show that g(x) does not match any of the two possibilities above.
Answer:
Step-by-step explanation:
1. A
2. 6/10; 1/10
5's are in 10
6/10
Hey there :)
( 5y + 9 )( 6y - 1 )
We need to use FOIL to expand, that is
First Terms
Outer Terms
Inner Terms
Last Terms
First Outer Inner Last
( 5y )( 6y ) + ( 5y )( - 1 ) + 9 ( 6y ) + 9 ( - 1 )
30y² - 5y + 54y - 9
Combine, if any, the like-terms
30y² + 49y - 9
To rotate clockwise 90 degrees from a point (x, y) the image will be (y, -x)
In this case given the point (-1, 1), the image will be (1, -(-1)) or (1, 1)