I believe the expression would be 7(g)+7
I'm in 7th grade u want those math problems???
Answer:
Erie to Rochester is 145 miles
Step-by-step explanation:
If we designate the points of interest as C, E, and R, we are told that ...
CE + ER = CR . . . . . the various distances are segments of a straight line
For CE = 94 and CR = 239, we can fill in the given information and solve for ER.
94 + ER = 239
ER = 239 -94 . . . . . . subtract 94 from both sides of the equation
ER = 145
The distance from Erie to Rochester is 145 miles.
The rational root theorem states that the rational roots of a polynomial can only be in the form p/q, where p divides the constant term, and q divides the leading term.
In your case, both the leading term 5 and the constant term 11 are primes, so their only divisors are 1 and themselves.
So, the only feasible solutions are
![\pm\dfrac{11}{5},\quad\pm 11,\quad \pm\dfrac{1}{5}, \pm 1](https://tex.z-dn.net/?f=%5Cpm%5Cdfrac%7B11%7D%7B5%7D%2C%5Cquad%5Cpm%2011%2C%5Cquad%20%5Cpm%5Cdfrac%7B1%7D%7B5%7D%2C%20%5Cpm%201)
For the record, in this case, none of the feasible solutions are actually a root of the polynomial.