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2 years ago

Explain why the system of equations - 2x + y=6 and y-2x = 4 has no solution

1 answer:

7 0

Hi, so basically when you solve the system, you will end up with 6=4 which is clearly not true so the system has no solution. i’ve put the working in the image.

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I need help with this one too

natali 33 [55]

Hey there! :)

Answer:

y = 11.

Step-by-step explanation:

Set both of the equations equal:

5x - 9 = x² - 3x + 7

Rearrange the equation:

0 = x² - 3x - 5x + 9 + 7

Combine like terms:

0 = x² - 8x + 16

Factor:

0 = (x -4)²

Solve for x:

0 = x - 4

x = 4.

Plug this into an equation to solve for 'y':

y = 5(4) - 9

y = 20 - 9

y = 11.

3 0

3 years ago

Read 2 more answers

If 5<2x+3<11, what is the possible range of value of -4x-6

Lady bird [3.3K]

Answer:

-10 > (-4x - 6) > -22

Step-by-step explanation:

Given inequality is 5 < 2x + 3 < 11

Now we will multiply this inequality by (-2) resulting,

5(-2) > (2x + 3)(-2) > 11(-2)

-10 > (-4x - 6) > -22 (Sign of inequality gets reversed when the inequality is multiplied or divided by a negative number)

Therefore, the possible range of (-4x - 6) is between -22 and -10.

4 0

3 years ago

Please answer this, I need help. Thank you!!

murzikaleks [220]

Answer:

1 and 2 and 4

Step-by-step explanation:

5 0

3 years ago

a card is chosen from a standard deck of cards. what is the probability that the card is a queen, given that the card is a club?

Dmitrij [34]

Answer:

Probability that card is queen given that card is club is $\frac{4}{13}$

Step-by-step explanation:

Given : A card is chosen from a standard deck of cards.

To find : What is the probability that the card is a queen, given that the card is a club?

Solution : It is the conditional probability

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

Let A is probability that card is queen.

Let B is the probability that card is a club.

Probability that card is queen given card is club $P(A\cap B)=\frac{4}{52}=\frac{1}{13}$

Probability that card is club from deck of 52 cards $P(B)=\frac{13}{52}=\frac{1}{4}$

To find probability that card is queen given that card is club $P(A|B)$

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

$P(A|B)=\frac{\frac{1}{13}}{\frac{1}{4}}$

$P(A|B)=\frac{1\times4}{13\times 1}=\frac{4}{13}$

Therefore, Option A is correct.

Probability that card is queen given that card is club is $\frac{4}{13}$

7 0

3 years ago

Read 2 more answers

Help me please Mid terms Suck

Leni [432]

Answer:

B. 8³ in. ²

Step-by-step explanation:

The sum of 4³*2³= 512

And the sum of 8³ = 512

Another way to do this if the numbers have the same exponent just multiply the numbers by each other to get the answer.

Example: 4³*2³

Multiply 4*2 = 8

Put the exponent 8³

Hope this helps ya!

7 0

2 years ago