To find the height, you will utilize the formula for area of a trapezoid. A = h(b1 +b2)/2. h is the height, b1 is the the first base, and b2 is the second base. When you substitute the information given to us in the question, the equation that needs solved is 37.4 = h(6.4 + 12.3)/2. You should multiply both sides by 2 to undo the dividing by 2. This gives you 74.8 = h (18.7). To solve for the height, divide both sides by 18.7. This gives us a cross sections height of 4 meters. This is the answer!
Answer:
B: 19.3
Step-by-step explanation:
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The answer is c explanation
Answer: a) α = 0.7927, b) at u=14.8, β = 0.99767, at u = 14.9, β= 0.2073
Step-by-step explanation: a) from the question, u= population mean = 15 and x= sample mean = 14.9
σ = population standard deviation = 0.5, n = sample size = 50.
We get the probability of committing a type 1 error by using the z score.
Z = x - u/(σ/√n)
Z = 14.9 - 15/(0.5/√50)
Z = - 0.1/0.0707
Z = - 1.41.
By checking the the probabilistic value attached to this z score using a standard normal distribution table whose area is to the left of the distribution, we have that
P(z=-1.41) = 0.7927.
Hence the probability of committing a type 1 error is 0.7927
b)
at x = 14.8 ( I let ua=x=14.8)
Z = x - u/(σ/√n)
Z = 14.8 - 15/(0.5/√50)
Z = - 0.2/ 0.0707
Z = - 2.83
Using the standard normal distribution table, we have that
P(z=-2.38) = 0.00233.
But α + β = 1
Where α= probability of committing a type 1 error
β = probability of committing a type 2 error.
β = 1 - α
β = 1 - 0.00233
β = 0.99767
At x = 14.9
Z = x - u/(σ/√n)
Z = 14.9 - 15/(0.5/√50)
Z = - 0.1/0.0707
Z = - 1.41.
P(z=-1.41) = 0.7927.
α = 0.7927.
But α + β = 1
β = 1 - 0.7927
β = 0.2073
Answer:
It will take approximately 17 years
Step-by-step explanation:
Let the initial investment be x
The investment plus the principal yields 3x
The interest is thus 3x-x = 2x
Formula for simple interest is;
I = PRT/100
R is rate = 12%
T is time = ?
x =$2,000 which is the principal
2x = x * 12 * T/100
2 = 12t/100
12t = 200
t = 200/12
t = 16.67 which is approximately 17 years