<span>a.
</span>Do you
have sufficient funds to estimate the population mean for the attribute of
interest with a 95% confidence interval 4 units width? Assume that sd= 12
n= {[(Zalpha/2)^2]*[sd]^2}/
se^2
n=
(1.96)^2*(12)^2/ (2)^2
n=
138.297 rounded up to 139
<span>There
is not enough funds for this one
since you’ll need 139 pieces and it costs 10 a piece, you’ll need 1390.</span>
b.
90% confidence interval
n= {[(Zalpha/2)^2]*[sd]^2}/
se^2
n=
(1.645)^2*(12)^2/ (2)^2
n=98
There is enough
funds since 98 pieces for 10 a piece is equal to 980.
Answer:
48
Step-by-step explanation:
Order.
9, 12, 12, 14, 15, 16, 18, 21
Now split into quarters.
9, 12, 12, 14, 15, 16, 18, 21
| | |
(1) (3)
Determine the values of (1) and (3) by using medians.
14 + 12 + 12 + 9 / 4
47 / 4
approx. 12
So Q1 = 12.
15 + 16 + 18 + 21 / 4
70 / 4
approx. 17
Therefore the answer is C I think. I have not done this ever before. All the knowledge I did was from research lol
It would be C because if you take out the four, the coefficients are multiples of 4 so it simplifies down.
Answer:
5.415m and 2.585m long
Step-by-step explanation:
For a right triangle
hyp^2 = opp^2 + adj^2 (Pythagoras theorem)
Given
hypotenuse = 6m
height(opposite) = h meters
Adjacent = (8-h)m
Substitute into the expression above;
6² = h²+(8-h)²
36 = h²+64-16h+h²
36 = 2h²-16h+64
2h²-16h+64-36 = 0
2h²-16h+28= 0
Divide through by 2
h²-8h+14 = 0
Using the general formula
h = 8±√8²-4(14)/2
h = 8±√64-56/2
h = 8±√8/2
h = 8±2.83/2
h = 8+2.83/2 and 8-2.83/2
h = 10.83/2 and 5.17/2
h = 5.415 and 2.585
hence the length of the height of the right triangle are 5.415m and 2.585m long
