16² = 18² + 19² - 2(18)(19)cos(z)
256 = 324 + 361 - (684)cos(z)
256 = 685 - (684)cos(z)
-429 = -684cos(z)
cos(z) = -429/-684
z = cos⁻¹ (0.627)
z = cos⁻¹ (cos 51) [ Cos 51 = 0.627 ]
z = 51
In short, Your Answer would be: 51
Hope this helps!
UW=12KL because ku and wl are intersecting points so that means UW=12KL
Answer:
see explanation
Step-by-step explanation:
(1)
the sine of an angle = 
(a)
here the opposite is 12 and the hypotenuse is 13
12 is the side opposite ∠DEF ← required angle
(b)
the tangent of an angle = 
here the opposite is 5 and the adjacent is 12
∠DFE ← required angle
(2)
to calculate AB use Pythagoras' identity in the right triangle
AB² = 2² + 3² = 4 + 9 = 13, hence
AB =
≈ 3.6 ( to nearest tenth )
tanB =
⇒ B = 33.7°
tanA =
⇒ A = 56.3°
Answer:
3*2-7y=9
or,6-7y=9
or,-7y=9-6
or,-7y=3
or y=3/-7
therefore the value of y=3/-7