Answer:
Using z score formula:
X = z ∂ + µ
= 157.833
Step-by-step explanation:
Solution:
Mean = µ = 1262
Standard deviation = ∂ = 117
(a) 28th percentile for the number of chocolate chip.
P( z < z) = 28%
= 0.28
P( z<- 0.58) = 0.28
Z = -0.58
By using z score formula:
Z = x - µ /∂
-0.58= x – 117 / 1262
X = (- 0.58)(117) + (1262)
= 1194.14
(b) Middle 97% of bag.
P(-z < z < z) = 97%
= 0.97
P( z < z) – p(z < -z) = 0.97
2p(z < z) -1 = 0.97
2p (z < z) = 1 + 0.97
P(z < z) = 1.97 / 2
= 0.99
P(z < 2.33) = 0.99
Z ± 2.33
By using z score formula:
Z = x - µ / ∂
X = z ∂ + µ
= - 2.33 x 117 + 1262
=989.39
Z = 2.33
X = z ∂ + µ
= 2.33 x 117 + 1262
=1533.61
(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate.
By using standard normal table,
The z dist’n formula:
P(z < z ) = 25%
=0.25
P(z < -0.6745) = 0.25
Z = 0.6745
Using z score formula:
X = z∂ + µ
= - 0.6745 x 117 + 1262
= 1183.0835
First quartile = Q1 =1183.0835
The third quartile is:
P(z<z) = 75%
= 0.75
P(z < 0.6745) = 0.75
Z = 0.6745
Using z score formula:
X = z ∂ + µ
= 0.6745 x 117 + 1262
= 1340.9165
IQR = Q3 – Q1
= 1340.9165 – 1183.0835
= 157.833
Answer:
-4≤ g
Step-by-step explanation:
subtract the 7 to move the numbers to one side
Answer:
X = 3
Step-by-step explanation:
First count the amount of X's. There are 5 and it is plus two. Both sides should be equal in value so you have to set up your equation.
5x + 2 = 17
Then Solve For X
5x + 2 = 17
Subtract 2 from both sides
5x = 15
Divide by 5
X = 3
Check your answer
5(3) +2 = 17
15 + 2 = 17
17 = 17
It is correct!
Pythagorean theorem: a^2 + b^2 = c^2
a^2 + 16^2 = 65^2
a^2 + 256 = 4225
a^2 = 3969
a = 63
Perimeter: add all sides
63 + 16 + 65 = 144
Solution: 144 feet
Answer:
B. 3(a + 7) + 3/(a + 2)
Step-by-step explanation:
Just substitute (a+2) in for every (x) in the equation:
f(a + 2) = 3 ((a + 2) + 5) + 4/(a+2)
= 3 (a + 7) + 4/(a+2)
