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3 years ago

Write the equation. Solve for x.

Mathematics

1 answer:

strojnjashka [21]3 years ago

7 0

Answer:

X = 3

Step-by-step explanation:

First count the amount of X's. There are 5 and it is plus two. Both sides should be equal in value so you have to set up your equation.

5x + 2 = 17

Then Solve For X

5x + 2 = 17

Subtract 2 from both sides

5x = 15

Divide by 5

X = 3

Check your answer

5(3) +2 = 17

15 + 2 = 17

17 = 17

It is correct!

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Help!! Answer !!! about to run out of time in test!!

Gemiola [76]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

$\qquad \sf \dashrightarrow \: h {}^{2} = {8}^{2} + {6}^{2}$

$\qquad \sf \dashrightarrow \: h {}^{2} = {36}^{} + {64}^{}$

$\qquad \sf \dashrightarrow \: h {}^{2} = 100$

$\qquad \sf \dashrightarrow \: h {}^{} = \sqrt{100}$

$\qquad \sf \dashrightarrow \: h {}^{} = {10}$

Now, let's find the asked values ~

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{opposite \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{3}{5} \: or \: 0.6 \: units$

For Cos y :

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{adjcant \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{3}{5} \: or \: 0.6 \: units$

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0

2 years ago

What is an equation of the line that passes through the point ( 6 , − 2 ) (6,−2) and is perpendicular to the line 6 x + y = 2 6x

Diano4ka-milaya [45]

Answer:

An equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

$y=\frac{1}{6}x-3$

Step-by-step explanation:

We know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept.

Given the line

6x+y=2

Simplifying the equation to write into the slope-intercept form

y = -6x+2

So, the slope = -6

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line.

Thus, the slope of the perpendicular line will be: -1/-6 = 1/6

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 1/6 and the point (6, -2)

$y-\left(-2\right)=\frac{1}{6}\left(x-6\right)$

$y+2=\frac{1}{6}\left(x-6\right)$

subtract 2 from both sides

$y+2-2=\frac{1}{6}\left(x-6\right)-2$

$y=\frac{1}{6}x-3$

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

$y=\frac{1}{6}x-3$

5 0

2 years ago

4 / 3 is equal to 12 / k<br> What does k equal?

Natali5045456 [20]

Answer:

k=9

Step-by-step explanation:

4/3 = 8/6 = 12/9

8 0

3 years ago

Read 2 more answers

Help me plz u will make my day

iris [78.8K]

Answer:

K=13

Step-by-step explanation:

So first, we subtract 13 with 3/4 (That comes from 4 3/4) and we get 12 1/4.

And then, we subtract 12 1/4 with 4, and we get 8 1/4

Have I made your day?

4 0

3 years ago

What is the factored form of this expression? 4t2 − 27t + 18

seraphim [82]

Answer:

(4t − 3) (t − 6)

Step-by-step explanation:

Using AC method:

Given a quadratic ax² + bx + c, find factors of ac that add up to b. Divide those factors by a and reduce. The denominators become the coefficients and the numerators become the constants.

Here, a = 4, b = -27, and c = 18.

ac = 4 × 18 = 72

Factors of 72 that add up to -27: -3 and -24

Divide factors by a: -3/4 and -24/4

Reduce: -3/4 and -6/1

So the factored expression is:

(4t − 3) (t − 6)

5 0

3 years ago