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3 years ago

14

Identify the missing digit: 5_8x6-3528

2 answers:

blagie [28]3 years ago

8 0

Answer:

The missing digit is 8

Step-by-step explanation:

3528/6 = 588

postnew [5]3 years ago

7 0

Answer:

the missing digit is 8

Step-by-step explanation:

3528÷6=5<u>8</u>8.

^

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I think is C like I said not quite sure...

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3 years ago

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a 120 watt light bulb uses about 0.1 kilowatt of electricity per hour. if electricity costs 0.20 per kilowatt hour, how much doe

Allushta [10]

A 120 watt light-bulb is a 0.120 kilowatt light bulb.

In one hour, it uses 0.120 kilowatt-hour of energy.

If electrical energy costs $0.20 per kilowatt hour, then that light bulb costs

(0.120 kilowatt-hour / hour) x (0.20 dollar / kilowatt-hour) =

(0.120 x $0.20 / hour) =

$0.024 / hour = <span>2.4¢ per hour </span>

5 0

4 years ago

Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)

DiKsa [7]

Answer:

The standard equation of the sphere is $(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Let the first endpoint be represented as $(x_{1}, y_{1}, z_{1})$ and the second endpoint be $(x_{2}, y_{2}, z_{2})$ .

Hence,

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Midpoint = $(\frac{3 + 7 }{2}, \frac{-2+12 }{2}, \frac{4 + 4 }{2})$

Midpoint = $(\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\$

Midpoint = $(5, 5, 4)$

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

$d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2} }$

$d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}$

$d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}$

$d = \sqrt{16 +196 + 0$

$d =\sqrt{212}$

$d = 2\sqrt{53}$

This is the diameter

To find the radius, r

From $Radius = \frac{Diameter}{2}$

$Radius = \frac{2\sqrt{53} }{2}$

∴ $Radius = \sqrt{53}$

r = $\sqrt{53}$

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is $(5, 5, 4)$

Radius of the sphere is $\sqrt{53}$

The equation of a sphere of radius r and center $(h,k,l)$ is given by

$(x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}$

Hence, the equation of the sphere of radius $\sqrt{53}$ and center $(5, 5, 4)$ is

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}$

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

This is the standard equation of the sphere

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3 years ago

What is 27 over 40 as a decimal

baherus [9]

27 divided by 40 is equal to 0.675.

5 0

3 years ago

PLEASE HELP ASAP WILL MARK BRANLIEST<br><br> did i get the right answer or is it wrong?

Nesterboy [21]

Answer:

<h2><em><u>62</u></em><em><u>.</u></em><em><u>2</u></em></h2>

Step-by-step explanation:

4n × 2 + 43

<em>[</em><em>By</em><em> </em><em>putting</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>n</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>4</em><em>]</em>

= (4 ×2.4) × 2 + 43

= 9.6 × 2 + 43

= 19.2 + 43

= <em><u>62.2 (Ans)</u></em>

4 0

3 years ago

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