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valentinak56 [21]
3 years ago
5

How can we tell the difference between a common multiple problem and a common factor problem?

Mathematics
1 answer:
Vinvika [58]3 years ago
3 0
Its in the wrist my boy man thing
You might be interested in
Hi hello! please help me.
Simora [160]

Answer:

x= -4

Step-by-step explanation:

hope it's helpful to you

8 0
2 years ago
Read 2 more answers
Caroline babysat for two families - the Nelsons and the Smiths. Use the info below to compare her earnings.
algol13

Answer:

She earns $6.50 from the Smiths which is 25 cents more than she earns at the Nelsons.

Step-by-step explanation:

To solve this problem you must find the hourly rate she earns at the Smiths.  This will allow you to compare to the hourly rate that is given for the Nelsons.  To find the Smiths hourly rate divide $39 by the 6 hours she babysat there.  This will have the hourly rate.  39/6=6.5.  This means she earns $6.50 an hour for the Smiths.  When comparing the rates it is clear that she earned 25 cents more at the Smiths.

7 0
3 years ago
The scatterplot represents the total fee for hours renting a bike. The line of best fit for the data is y = 6.855x + 10.215.
shepuryov [24]

The table shows the correct residual values for the data set regarding the scatterplot is D. A 3-column table with 5 rows. The first column is labeled x with entries 1, 2, 3, 4, 5.

<h3>What is a scatterplot?</h3>

It should be noted that a scatterplot simply means a type of data display which shows the relationship between the variables.

In this case, the table shows the correct residual values for the data set regarding the scatterplot is a 3-column table with 5 rows. The first column is labeled x with entries 1, 2, 3, 4, 5.

The second column is labeled given with entries 14.95, 25.50, 32, 38.95, 42.50. The third column is labeled residual value with entries negative 2.12, 1.575, negative 1.22, 1.315, negative 1.99.

Learn more about scatter plot on:

brainly.com/question/6592115

#SPJ1

6 0
2 years ago
If the circumference of a circle measures
RoseWind [281]
<h2>Therefore the area of the circle is =289\pi cm^2</h2>

Step-by-step explanation:

Given that the circumference of a circle measures 34 \pi cm

Let the radius of the circle be = r

Then circumference =2 \pi r cm

According to problem

2 \pi r = 34 \pi

⇔r = \frac {34}{2}

⇔r = 17 cm

Therefore the area of the circle is = \pi r^2

                                                    =\pi 17^2 cm^2

                                                    =289\pi  cm^2

8 0
3 years ago
I am extremely confused, can anyone help?​
JulijaS [17]

Answer:

So I did most of you table for you:

First blank:4

Second blank:-4

Third blank:-8

Fourth blank: Left to you: Just plug in 6 into 1/2x^2-5x+4 (I will check)

Fifth blank: Left to you: Just plug in 8 into 1/2x^2-5x+4 (I will check)

The graph is D.

Step-by-step explanation:

So they have a table to fill in and they tell you in the first row what they want you to plug in

So the table is asking us to answer this:

What is h(0),h(2),h(4),h(6), and h(8).

h(0) means to replace x with 0 in \frac{1}{2} x^2-5x+4.

\frac{1}{2}(0)^2-5(0)+4

0-0+4

0+4

4

So the first blank is 4 since h(0)=4.

h(2) means to replace x with 2 in \frac{1}{2} x^2-5x+4.

\frac{1}{2} (2)^2-5(2)+4

\frac{1}{2} (4)-10+4

2-10+4

-8+4

-4

So the second blank is -4 since h(2)=-4.

h(4) means to replace x with 4 in \frac{1}{2} x^2-5x+4.

\frac{1}{2}(4)^2-5(4)+4

\frac{1}{2}(16)-20+4

8-20+4

-12+4

-8

So the third blank is -8 since h(4)=-8

Maybe you can try the last 2 blanks in the table part. That is try computing h(6) and h(8). I will check it for you.

Now the points I have so far are (0,4) from the h(0)=4, (2,-4) from the h(2)=-4, and (4,-8) from the h(4)=-8.

I'm looking for a graph that goes through these points (0,4) , (2,-4) , and (4,-8).

By the way the only graphs that are worth looking at is C and D because they are open up.  I know my curve for h(x)=1/2x^2-5x+4 should be a parabola open up because 1/2 is positive and 1/2 is the coefficient of x^2.

So Graph C has y-intercept (0,10) not (0,4) so Graph C is not right.

Graph D has y-intercept (0,4).  It also goes through (2,-4) and (4,-8).  

I don't know if you notice but the x-axis and y-axis are going up by two's in each graph.

7 0
3 years ago
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