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Daniel [21]
3 years ago
11

If you come to a stumbling block and can't think of any more ideas, what could you do? select all that apply 2pts.

Computers and Technology
2 answers:
Ira Lisetskai [31]3 years ago
8 0

If you come to a stumbling block and can't think of any more ideas, what could you do? ALL OF THESE

1 expand on your favorite idea so far even if you don't think it will work. Sometimes you'll find a solution where you least expect it.

2 go with the ideas you've come up with this far. Moving forward and the design process will be encouraging.

3 rephrase your problem question. Looking at the problem from a different perspective can Inspire new ideas

4 take a break and come back later with a fresh mind. A clear mind will give you a new perspective
ANEK [815]3 years ago
7 0

When you have a mental block or in the midst of a rut, you can choose to implement several strategies that would help you escape this condition. Based on the options available for the question given, you can choose to:

  • [3] Rephrase your problem question. Looking at the problem from a different perspective can Inspire new ideas
  • [4] Take a break and come back later with a fresh mind. A clear mind will give you a new perspective

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What is one requirement for achieving Continuous Deployment
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Answer:

You need to get everything in version control. You need to automate the entire environment creation process.

Explanation:

You need a deployment pipeline where you can create test and production environments, and then deploy code into them, entirely on demand.

hope this helped ^^

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3 years ago
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This program is to compute and write to a file the GPA for student scores read from an input file. The point values of the grade
VARVARA [1.3K]

Answer:

#Take input from the user

filename=input('Enter name of input file: ')

total_units=0#Total number of units for a student

total_score=0#Total score of a student

#Assign a score to each grade. I have reduced 0.33 for each grade. Change here if you need to

grade={'A':4.0,'A-':3.67,'B+':3.34,'B':3.01,'B-':2.68,'C+':2.35,'C':2.02,'C-':1.69,'D+':1.36,'D':1.03}

try:

with open(filename,"r") as input_file:#Open the file for input(reading)

output_file=open("GPA_output.txt","w") #Create and open GPA_output.txt if it doesn't exist for writing

for student_record in input_file:#read from input file

if("," in student_record):#if there is a , that means this is the student name

student_name=student_record.strip('\n')#Remove \n from student name

continue

else:

if(" " in student_record):#If a line contains spaces then its the student's grades for a course

student=student_record.split(" ")#Split to find the coursename, units and grade

#student[0]=coursename student[1]=units student[2]=grade

total_units+=int(student[1])#Calculate total units for 1 student

total_score+=int(student[1])*grade[student[2].strip('\n')]#Find the total score of a student

#grade[student[2]] will lookup for the score that we initialized earlier

#if student has a grade as A then this will look up as grade['A'] which will return 4

#Find the total score as product of this grade and units for this course

continue

else:

if(total_units>0):#Check if score has been calculated for a student earlier

print("in")

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

if(total_units>0):#Essential for the case when the file doesn't end with a new line(Check if total_units is not 0) which means a record is pending

#to be written to the file

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

input_file.close()#Close the input file

output_file.close()#Close the output file

except IOError as e:

print("Problem in Opening the required file")#Print a message if file cannot be opened

Explanation:

The program has been tested for all 3 scenarios mentioned i.e.

a. If the file ends without \n

b. If the file ends with 2 \n

c. If the file ends with 1 \n

PS: The Program will run irrespective of how it ends. Even if there are many \n at the end of file, the program will be fine.

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Low-Level formatting is usually performed by the purchaser of the disk.

<h3>What is low-level formatting?</h3>

Low-Level formatting can be defined as is performed at the factory which electronically creates the hard drive tracks and sectors and tests for bad spots on a disk surface.

Low-level formatting is usually performed by the purchaser of the disk device.

Therefore, B is the correct option.

Learn more about Low-level formatting here:

brainly.com/question/13797778

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