5. Which energy transformation would friction

The density of lead is 11.3 g/cm3. what mass of lead is required to make a 1.00 cm3 fishing sinker?

Elza [17]

The mass of lead required to make a 1.00 cm3 fishing sinker is 11.3g.

What is mass?

Mass is a metric used in physics to express inertia, a fundamental characteristic of all matter. A mass of matter's resistance to altering its direction or speed in response to the application of a force is what it essentially is. The change that an applied force produces is smaller the more mass a body has.

Given :

Density of lead = 11.3 g/cm3

Volume of sinker = 1.00 cm3

One of a substance's attributes is density, which is calculated by dividing the mass by the volume. Mathematically:

Density : Mass / volume

therefore after putting the values,

mass= 11.3g

To learn more about density click on the link below:

brainly.com/question/18939565

#SPJ4

8 0

2 years ago

USATESTPREP

natulia [17]

Answer:

C, D, and E

Explanation:

5 0

2 years ago

Suppose a two-level system is in a bath with temperature 247 K. The energy difference between the two states is 1.1 × 10-21 J. W

Alik [6]

Answer:

The probability of higher energy state is 0.4200.

Explanation:

Given that,

Temperature = 247 K

Energy difference between two states $E_{2}-E_{1}=1.1\times10^{-21}\ J$

We need to calculate the probability of higher energy state

Probability of $E_{1}= e^{-\beta E_{1}}$

Probability of $E_{2}= e^{-\beta E_{2}}$

The total probability is

$e^{-\beta E_{1}}+e^{-\beta E_{1}}=1$

Here, E₁ = lower energy state

E₂ = higher energy state

Put the value of E₁ in to the formula

$e^{-\beta(E_{2}-1.1\times10^{-21})}+e^{-\beta E_{1}}=1$

$e^{-\beta E_{2}}(e^{\beta 1.1\times10^{-21}}+1)=1$

$e^{\beta E_{2}}=\dfrac{1}{1+e^{\dfrac{1.1\times10^{-21}}{KT}}}$

Here, $\beta=\dfrac{1}{KT}$

Put the value into the formula

$e^{\beta E_{2}}=\dfrac{1}{1+e^{\dfrac{1.1\times10^{-21}}{1.380\times10^{-23}\times247}}}$

$e^{\beta E_{2}}=0.4200$

Hence, The probability of higher energy state is 0.4200.

4 0

3 years ago

I have two of these so if you think this is easy then another free ten points in my profile!

Agata [3.3K]

Answer:

z

Explanation:

x repersents a new moon and the others repersent quarter moons

(x is a new moon because new moons are often the phase when the moon is close to earths sun)

7 0

3 years ago

Read 2 more answers

You are a member of a geological team in Central Africa. Your team comes upon a wide river that is flowing east. You must determ

Dovator [93]

Answer:

(a). The width of the river is 90.5 m.

The current speed of the river is 3.96 m.

(b). The shortest time is 15.0 sec and we would end 59.4 m east of our starting point.

Explanation:

Given that,

Constant speed = 6.00 m/s

Time = 20.1 sec

Speed = 9.00 m/s

Time = 11.2 sec

We need to write a equation for to travel due north across the river,

Using equation for north

$v^2-c^2=\dfrac{w^2}{t^2}$

Put the value in the equation

$6.00^2-c^2=\dfrac{w^2}{(20.1)^2}$

$36-c^2=\dfrac{w^2}{404.01}$ ....(I)

We need to write a equation for to travel due south across the river,

Using equation for south

$v^2-c^2=\dfrac{w^2}{t^2}$

Put the value in the equation

$9.00^2-c^2=\dfrac{w^2}{(11.2)^2}$

$81-c^2=\dfrac{w^2}{125.44}$ ....(II)

(a). We need to calculate the wide of the river

Using equation (I) and (II)

$45=\dfrac{w^2}{125.44}-\dfrac{w^2}{404.01}$

$45=w^2(0.00549)$

$w^2=\dfrac{45}{0.00549}$

$w=\sqrt{\dfrac{45}{0.00549}}$

$w=90.5$

We need to calculate the current speed

Using equation (I)

$36-c^2=\dfrac{(90.5)^2}{(20.1)^2}$

$36-c^2=20.27$

$c^2=20.27-36$

$c=\sqrt{15.73}$

$c=3.96\ m/s$

(b). We need to calculate the shortest time

Using formula of time

$t=\dfrac{d}{v}$

$t=\dfrac{90.5}{6}$

$t=15.0\ sec$

We need to calculate the distance

Using formula of distance

$d=vt$

$d=3.96\times15.0$

$d=59.4\ m$

Hence, (a). The width of the river is 90.5 m.

The current speed of the river is 3.96 m.

(b). The shortest time is 15.0 sec and we would end 59.4 m east of our starting point.

3 0

4 years ago