Answer:
Continuous
Explanation:
A circuit can only light up a lightbulb if there is a continuous path for electricity to travel from one end of the energy source to the other end.
<h3><u>Given</u><u>:</u><u>-</u></h3>
Force,F = 100 N
Acceleration,a = 5 m/s²
<h3><u>To</u><u> </u><u>be</u><u> </u><u>calculated:-</u><u> </u></h3>
Calculate the mass of the box .
<h3><u>Formula</u><u> </u><u>used:-</u><u> </u></h3>

<h3><u>Solution:-</u><u> </u></h3>

★ Substituting the values in the above formula,we get:



Your pancreas is an organ that is apart of the digestive system. It produces insulin and other enzymes that helps break down the food you eat.
It is found across the back of the abdomen, that is behind the stomach.
F=ma
Force= mass × acceleration
1 mol of photons contained a number of photons equal to Avogadro number:

The total energy of the mole of photons is

, so the energy of a single photon is the total energy divided by the number of photons:

The energy of a single photon is related to its frequency f:

where h is the Planck constant. From this formula, we find the frequency of the photons in the problem:

And from the frequency we can finally calculate the wavelength

, using the relationship between wavelength, frequency and speed of light (c) for photons: