Answer:
length=53 in
width= 23 in
Step-by-step explanation:
First, we know that each corner has now a square of 6 in long, so the heigth of the box will be of this size (as you can see in the picture attached). Then, the length and the width of the box would be the same as the piece, but with 12 in less. Therefore the equations to solve the problem are:
We factorize the 6 and we get:
Finally we solve for x, and we get the initial dimensions of the piece of metal:
Combine the k’s 17k
Combine the m’s -8m
Combine the n’s 12n
17k-8m+12n
Total possibilities would be:
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
You want 5 on at-least one, so mark 5th column & 5th raw.
There are 6 in both lines with 1 common = (5,5)
In short, Your Answer would be 11
Hope this helps!
Answer:
the answer is D (^_^ ) hope this helps
Step-by-step explanation:
