Answer: 5040 7-digit numbers
Step-by-step explanation:
Permutations:
1: 1 ==> 1 permutation ==> 1 ==> 1!
12: 12, 21 ==> 2 permutations ==> 1*2 ==> 2!
123: 123, 132, 213, 231, 312, 321 ==> 6 permutations ==> 1*2*3 ==> 3!
7-digits: 7!=
1*2*3*4*5*6*7=5040 7-digit numbers
Answer:
Joe shoveled 6, Jill shoveled 9
Step-by-step explanation:
Answer:
I have solved the question in the picture in two different ways : simplification and factorisation I hope you find it useful bye:)
<span>idk if this exactly correct but i tried
1 Find and add the lengths of all the polygon's sides
2.Multiply the lengths of equal sides by the number of equal sides.
3 Multiply a regular polygon's side length by the number of sides.
4 Alternatively, use the area and apothegm of the polygon.
</span>
Answer: number 3, 35
Step-by-step explanation: i promise
