Answer:
The first four terms of the sequence are-6, -2, 2 and 6
Step-by-step explanation:
The given sequence is 
In order to find the first four term of the sequence we put n =0, 1, 2 and 3.
For n =0

For n =1

For n =2

For n =3

Therefore, the first four terms of the sequence are
-6, -2, 2 and 6
Answer: C
Step-by-step explanation: Hope this help :D
F(x) = x^5 - 1; g(x) = 5x^2; h(x) = 2x
Answer:
The correct question is
Which is the best approximation to a solution of the equation
e^(2x) = 2e^{x) + 3?
we have that
e^(2x) = 2e^{x) + 3-----------> e^(2x)- 2e^{x) - 3=0
the term
e^(2x)- 2e^{x)----------> (e^x)²-2e^(x)*(1)+1²-1²------> (e^x-1)²-1
then
e^(2x)- 2e^{x) - 3=0--------> (e^x-1)²-1-3=0------> (e^x-1)²=4
(e^x-1)=2--------> e^x=3
x*ln(e)=ln(3)---------> x=ln(3)
ln(3)=1.10
hence
x=1.10
the answer is x=1.10