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Mice21 [21]
2 years ago
5

Given: g(x) = x - 4 and h(x) = 2x - 8. What is g(h(1011?​

Mathematics
2 answers:
ANEK [815]2 years ago
8 0

Answer:

g(h(1011)) = 2010

Step-by-step explanation:

Given

g(x) = x - 4

h(x) =2x - 8

Required

g(h(1011)

First, we calculate g(h(x))

g(x) = x - 4

Substitute h(x) for x

g(h(x)) = h(x) -4

Substitute h(x) =2x - 8

g(h(x)) = 2x - 8 -4

g(h(x)) = 2x -12

Substitute 1011 for x

g(h(1011)) = 2*1011 -12

g(h(1011)) = 2022 -12

g(h(1011)) = 2010

ExtremeBDS [4]2 years ago
5 0

Answer:

6

Step-by-step explanation:

just did it on egde 2021

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Let g(x) = 2x and h(x) = x2 + 4. Evaluate (h ∘ g)(1). 2 8 10 4
Klio2033 [76]
Hello!

You can solve this by plugging 1 into g(x) and plugging the result into h(x).

g(x) = 2x
g(1) = 2(1)
g(1) = 2

h(x) = 2x + 4
h(g(1)) = 2(2) + 4
h(g(1)) = 4 + 4
h(g(1)) = 8

Answer:
<span>(h ∘ g)(1) = 8</span>
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Figure ABCDE was reflected across the line y=x to create figure A’B’C’D’E’.What are the coordinates of the pre-image of E’?
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Answer:

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Step-by-step explanation:

7 0
2 years ago
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According to a Los Angeles Times study of more than 1 million medical dispatches from to , the response time for medical aid var
-BARSIC- [3]

Answer:

A)Mean :10.65

Median =10.7

Mode : 10.7

B)Range = 3.5

Standard deviation :0.89916

C)The response time of 8.3 minutes should be considered an outlier in comparison to the other response times

Step-by-step explanation:

A)

Data : 11.8 ,10.3, 10.7, 10.6, 11.5, 8.3, 10.5, 10.9, 10.7, 11.2

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\Mean = \frac{11.8 +10.3+ 10.7+ 10.6+ 11.5+ 8.3+ 10.5+ 10.9+ 10.7+ 11.2}{10}

Mean = 10.65

Median: The mid value of the data

Data in ascending order

8.3

10.3

10.5

10.6

10.7

10.7

10.9

11.2

11.5

11.8

n=10(even)

Median = \frac{(\frac{n}{2})\text{th term}+(\frac{n}{2}+1)\text{th term}}{2}\\Median = \frac{(\frac{10}{2})\text{th term}+(\frac{10}{2}+1)\text{th term}}{2}\\Median = \frac{10.7+10.7}{2}\\Median = 10.7

Mode : the most occurring frequency

10.7 is occurring twice while others are occurring once

So, Mode is 10.7

B) Range = Maximum - Minimum=11.8-8.3=3.5

Standard deviation : \sqrt{\frac{\sum(x-\bar{x})^2}{n}}

Standard deviation :\sqrt{\frac{(11.8-10.65)^2+(10.3-10.65)^2+......+(10.9-10.65)^2+(10.7-10.65)^2+(11.2-10.65)^2}{10}}

Standard deviation :0.89916

C)

8.3

,10.3

,10.5

,10.6

,10.7

,10.7

,10.9

,11.2

,11.5

,11.8

For Q1 ( Median of lower quartile )

8.3

,10.3

,10.5

,10.6

,10.7

Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=10.5

For Q3( Median of Upper quartile )

10.7

,10.9

,11.2

,11.5

,11.8

Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=11.2

IQR = Q3-Q1=11.2-10.5=0.7

Range :(Q1-1.5IQR, Q3-1.5IQR)

Range :(10.5-1.5 \times 0.7, 11.2-1.5 \times 0.7)

Range :(9.45, 10.15)

8.3 does not lie in this interval

So, the response time of 8.3 minutes should be considered an outlier in comparison to the other response times

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2 years ago
Can anyone explain this to me-
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What is the figure?.......
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