Answer:
5
Step-by-step explanation:
1. in order to calculate all the required values, it needed to solve:

2. x≥5 means, that x∈[5;+∞), where beginnig is '5'.
Answer:
2^6
Step-by-step explanation:
2*2*2*2*2*2
There are six 2's multiplied together so the base is 2 and the exponent is 6
2^6
Answer:
84.5
Step-by-step explanation:
12.3(3)+11.9(4)=84.5
Answer:
Keenan's z-score was of 0.61.
Rachel's z-score was of 0.81.
Step-by-step explanation:
Z-score:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points.
This means that 
So



Keenan's z-score was of 0.61.
Rachel scored 78 points on an exam that had a mean score of 75 points and a standard deviation of 3.7 points.
This means that
. So



Rachel's z-score was of 0.81.