(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
Step-by-step explanation:
working g and everything is above
hope its of help
Solving for the amount of maturity given that it is compounded monthly for 1 year with an interest of 3%, we have the formula and solution below:
A = P (1+r/n)^rn
A = $5,000 (1.040417)
A =$5202.085
For compounded daily, we have the solution below:
A = $5,000 (1.040443)
A = $5202.215
The difference in amount is shown below:
Difference = $5202.215 - $5202.085
Difference = $0.13
