Answer:
2 touchdowns, 3 field goals
Step-by-step explanation:
The number of touchdowns cannot be more than 3, so it is relatively easy to find the solution by trial and error.
23 is not divisible by 3, so 0 touchdowns is not a solution
23 -7 = 16 is not divisible by 3, so 1 touchdown is not a solution
23 -14 = 9 is divisible by 3, so 2 touchdowns and 3 field goals is a solution
21 -21 = 2 is not divisible by 3, so there is only one solution.
It is four. So two and two you add them together to be four. Good job. Your learning :)
It depends if x is positive or negative and the same as in y
Answer:
im your best friend
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
