-4 is your answer hope this helps
Answer:
The first five terms of the given sequence
3, 6, 11, 18, 27
Step-by-step explanation:
It is given that,
an=n² +2
<u>To find the first five terms</u>
a₁ = 1² + 2 = 1 + 2 = 3
a₂ = 2² + 2 = 4 + 2 = 6
a₃ = 3² + 2 = 9 + 2 = 11
a₄ = 4² + 2 = 16 + 8 = 18
a₅ = 5² + 2 = 25 + 2 = 27
Therefore the first five terms of the given sequence
3, 6, 11, 18, 27
Answer:
f(2x + 4) = -4x² - 16x - 15
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
<u>Algebra I</u>
- Terms/Coefficients
- Expanding (FOIL)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
f(x) = 1 - x²
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em> [Function f(x)]: f(2x + 4) = 1 - (2x + 4)²
- Expand [FOIL]: f(2x + 4) = 1 - (4x² + 16x + 16)
- (Parenthesis) Distribute negative: f(2x + 4) = 1 - 4x² - 16x - 16
- Combine like terms: f(2x + 4) = -4x² -16x - 15
I think the answer is: 6 = -21
