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3 years ago

10

ms shaddal writes 3g = 51 and 15 16 17 on the board tell if each value in the set is a solution of the equation show your work b

rainly

1 answer:

Rudiy273 years ago

7 0

Answer:

17 is the solution to the equation

Step-by-step explanation:

3g=51

/3 /3

g=17

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Choose all of the problems that result in an answer of 8.5.

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Answer:E

Step-by-step explanation:

Type it all into a calculator

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3 years ago

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A researcher claims that the mean of the salaries of elementary school teachers is greater than the mean of the salaries of seco

Brut [27]

Answer:

$t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921$

$df=n_{A}+n_{B}-2=26+24-2=48$

Since is a one sided test the p value would be:

$p_v =P(t_{(48)}>1.921)=0.0303$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X_{A}=48250$ represent the mean of elementary teachers

$\bar X_{B}=45630$ represent the mean for secondary teachers

$s_{A}=3900$ represent the sample standard deviation for elementary teacher

$s_{B}=5530$ represent the sample standard deviation for secondary teachers

$n_{A}=26$ sample size selected

$n_{B}=24$ sample size selected

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean of the salaries of elementary school teachers is greater than the mean of the salaries of secondary school teachers, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{B}\leq 0$

Alternative hypothesis: $\mu_{A}-\mu_{B}>0$

We don't know the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{B})}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{A}+n_{B}-2=26+24-2=48$

Since is a one sided test the p value would be:

$p_v =P(t_{(48)}>1.921)=0.0303$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

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3 years ago

Marley and Kaitlyn are making duct tape wallets to sell at a craft fair

Mariana [72]

Answer:

16%

Step-by-step explanation:

20/125 = 0.16

0.16 x 100 = 16% (multiply by 100 to get a percentage)

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3 years ago

Cheryl has some oranges. she puts the oranges into p boxes of 3 oranges each and has 2 oranges left. Find the total number of or

Umnica [9.8K]

So she had x oranges

she put the oranges into p boxes with 3 in each box and had 2 left so

total=3 times p+2 or
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a lawn is in the shape of a rectangle with a length of 100 feet and a width of 45 feet. how many whole bags of fertilizer must b

leva [86]

Answer:

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Step-by-step explanation:

$45 \times 100 = 4500 \\ 4500 \div 2000 = 2.25$

you cant have 0.25 of a bag so you round up to 3.

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3 years ago