Answer:
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
Step-by-step explanation:
We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.
Firstly, Let X = women's gestation period
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= average gestation period = 270 days
= standard deviation = 9 days
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X
261)
P(X < 279) = P(
<
) = P(Z < 1) = 0.84134
P(X
261) = P(
) = P(Z
-1) = 1 - P(Z < 1)
= 1 - 0.84134 = 0.15866
<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>
Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
8x2+6x-2
I think! because 8,6, and 2 are all divisible by 2
and 3. Factor the quadratic
2(4x-1)(x+1)
7 1/3
I think this is it, i would like for u to get a second opinion.
Answer:
5,4
Step-by-step explanation:
here is the rule (4,-5) rotate 90 clockwise = (5,4)
4,-5 will put you in the 4 quadrant rotate it 90 clock wise Put you in the first quadrant
Answer: 60.5
Step-by-step explanation:
Since you’re solving for y, you want to get it by itself to get a clean reading answer of y= blank.
So in 6y=363 you would want get rid of that 6 from the y, do you would divide both sides by 6.
6y/6 = 363/6
And then you’d get
y=60.5 once you finish dividing.