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Misha Larkins [42]
3 years ago
14

Marathon Hours,Miles 0,0; 1,6; 2,11; 3,15; 4,21; 5,26.2. Cayla ran a marathon. The table shows which mile Cayla had finished at

the end of each hour. Find Cayla's rate in miles per hours from hours 2 to hour 3 of the marathon. A) 3 miles per hour B) 4 miles per hour Eliminate C) 5 miles per hour D) 6 miles per hour

Mathematics
2 answers:
stiv31 [10]3 years ago
5 0
The answer would be B) 4mph
MArishka [77]3 years ago
3 0

Answer:

The answer is B, 4 miles per hour

Step-by-step explanation:

See picture.

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A negative number raised to an odd power is_<br> negative.
Maslowich

Answer:

still

Step-by-step explanation:

just give yourself some examples

(-1)^1=-1

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Consider a finite population with five elements labeled A, B, C, D, and E. Ten possible simple random samples of size 2 can be s
LenKa [72]

Answer: 4/25

Step-by-step explanation:

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Helppp btw the number are (0,5) (2,2) (3,1) (4,-1)
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Your answer is (3,1) because if you graph the line that is the on off the line the other follow through
4 0
3 years ago
A2 = [1 2 3; 4 5 6; 7 8 9; 3 2 4; 6 5 4; 9 8 7]
34kurt

Answer:

Remember, a basis for the row space of a matrix A is the set of rows different of zero of the echelon form of A.

We need to find the echelon form of the matrix augmented matrix of the system A2x=b2

B=\left[\begin{array}{cccc}1&2&3&1\\4&5&6&1\\7&8&9&1\\3&2&4&1\\6&5&4&1\\9&8&7&1\end{array}\right]

We apply row operations:

1.

  • To row 2 we subtract row 1, 4 times.
  • To row 3 we subtract row 1, 7 times.
  • To row 4 we subtract row 1, 3 times.
  • To row 5 we subtract row 1, 6 times.
  • To row 6 we subtract row 1, 9 times.

We obtain the matrix

\left[\begin{array}{cccc}1&2&3&1\\0&-3&-6&-3\\0&-6&-12&-6\\0&-4&-5&-2\\0&-7&-14&-5\\0&-10&-20&-8\end{array}\right]

2.

  • We subtract row two twice to row three of the previous matrix.
  • we subtract 4/3 from row two to row 4.
  • we subtract 7/3 from row two to row 5.
  • we subtract 10/3 from row two to row 6.

We obtain the matrix

\left[\begin{array}{cccc}1&2&3&1\\0&-3&-6&-3\\0&0&0&0\\0&0&3&2\\0&0&0&2\\0&0&0&2\end{array}\right]

3.

we exchange rows three and four of the previous matrix and obtain the echelon form of the augmented matrix.

\left[\begin{array}{cccc}1&2&3&1\\0&-3&-6&-3\\0&0&3&2\\0&0&0&0\\0&0&0&2\\0&0&0&2\end{array}\right]

Since the only nonzero rows of the augmented matrix of the coefficient matrix are the first three, then the set

\{\left[\begin{array}{c}1\\2\\3\end{array}\right],\left[\begin{array}{c}0\\-3\\-6\end{array}\right],\left[\begin{array}{c}0\\0\\3\end{array}\right] \}

is a basis for Row (A2)

Now, observe that the last two rows of the echelon form of the augmented matrix have the last coordinate different of zero. Then, the system is inconsistent. This means that the system has no solutions.

4 0
3 years ago
Simplify: (4x)(-x^2)(5x^3)
Mekhanik [1.2K]

Answer:

-20 x^6

Step-by-step explanation:

(4x)(-x^2)(5x^3)

Multiply the numbers

4*-1 *5 = -20

Add the exponents

x^1 * x^2 * x^3

x^(1+2+3)

x^6

Multiply back together

-20 x^6

5 0
3 years ago
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