Answer:
Explanation:
Heat of vaporization is the amount of heat required to convert 1 mole of liquid substance to its vapor form.
Given :
Amount of heat required for 1 mol of water = 40.7 kJ/mol
According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number of particles.
1 mole of weighs = 18.02 g
Thus we can say:
18.02 g of requires heat = 40.7 kJ
Thus 5.6 g of requires heat = (1kJ=1000J)
Thus the energy required to completely vaporize 5.6 g of water at 100.°C is
The rate of change of (g)=0.024M/s when the rate of change of is – 0.012 M/s.
<h3>What is the rate of reaction?</h3>
Reaction rate, in chemistry, is the speed at which a chemical reaction proceeds.
→
Rate = \frac{-dcs_2}{dt} =\frac{-do_2}{dt} =\frac{+dco_2}{dt} =\frac{1dso_2}{dt}
Given:
The rate of change of (g)=0.024M/s
Hence, the rate of change of (g)=0.024M/s
Learn more about the rate of change here:
brainly.com/question/13103052
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Im pretty sure the answer would be 2. Bc that’s how many is shared between O2