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Whitepunk [10]
3 years ago
11

Find the volume of the cone and round to the nearest tenth.

Mathematics
1 answer:
strojnjashka [21]3 years ago
4 0

Answer:

V≈1960.4

Step-by-step explanation:

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Give some examples of items that weigh more than 1 ton
PilotLPTM [1.2K]
A ship, A car, A house, An elephant
8 0
3 years ago
The sum of the interior angles of a regular polygon is 1800 degrees. How many sides does is have? *
Rudik [331]

Answer:

12 sides

Step-by-step explanation:

To find the number of sides of a regular polygon with the sum of interior angles of 1800 degrees, we will follow the steps below;

first write down the formula for finding sum of the interior angle of a polygon

s= (n-2)180

where s is the sum of the interior angle and n is the number of side

from the question given, sum of the interior angle s=1800 degrees

substitute s=1800 degree into the formula and solve for n

s= (n-2)180

1800 = (n-2)180

divide both-side of the equation by 180

1800/180 = n-2

10 = n - 2

add 2 to both-side of the equation

10 + 2 = n

12 = n

n= 12

The polygon have 12 sides

5 0
3 years ago
How much is 2/7 of 1 3/4?
svlad2 [7]
The answer to your question is 2/7 is 1/2 of 1 3/4.
4 0
3 years ago
Read 2 more answers
Please help I’m stuck!!!
Anika [276]

Answer:

The value of angle B is 33.69°

Step-by-step explanation:

You can find out using Tangent Rule, tanθ = oppo./adj. where opposite and adjacent are the length of triangle :

oppo. = AC = 6 units

adj. = BC = 9 units

θ = ∠B

tan ∠B = AC/BC

tan ∠B = 6/9

∠B = tan^(-1) (6/9)

= 33.69° (near. hundredth)

3 0
3 years ago
Determine the measure of ∠Q, rounded to the nearest tenth of a degree.<br> images attached.
const2013 [10]

Answer:

D

Step-by-step explanation:

Using the Sine rule in Δ QRS , that is

\frac{q}{sinQ} = \frac{r}{sinR} , that is

\frac{15}{sinQ} = \frac{12}{sin50.1} ( cross- multiply )

12× sinQ = 15 × sin50.1° ( divide both sides by 12 )

sinQ = \frac{15sin50.1}{12} , thus

Q = sin^{-1} ( \frac{15sin50.1}{12} ) ≈ 73.5° ( to the nearest tenth )

8 0
4 years ago
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