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Whitepunk [10]
3 years ago
11

Find the volume of the cone and round to the nearest tenth.

Mathematics
1 answer:
strojnjashka [21]3 years ago
4 0

Answer:

V≈1960.4

Step-by-step explanation:

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How do you do <br> (2/3) (-4) (9)
DochEvi [55]

Answer:

Since 3 is evenly divided by 9, we can multiply just one term to get a common denominator. Multiply 2 by 3, and get 6, then we multiply 3 by 3 and get 9.

Step-by-step explanation:

7 0
3 years ago
Iliana was part of a group that was working on changing 0.4 repeated to a fraction. Each member of the group had a different ans
amm1812
\bf 0.444444444\overline{4}\impliedby \textit{and keeps on going}\\\\&#10;-------------------------------\\\\&#10;\textit{let's say }\boxed{x=0.444444444\overline{4}}\quad \textit{ thus }10\cdot x=4.44444444\overline{4}&#10;\\\\\\&#10;\textit{wait a minute! }4.44444444\overline{4}\textit{ is really just }4+0.444444444\overline{4}

\bf \textit{but we know }x=0.444444444\overline{4} \textit{ so then }4+0.444444444\overline{4}=\boxed{4+x}&#10;\\\\\\&#10;\textit{wait a second! }10\cdot x\implies 10x=4.444444444\overline{4}=4+x&#10;\\\\\\&#10;thus\qquad 10x=4+x\implies 10x-x=4\implies 9x=4\implies \boxed{x=\cfrac{4}{9}}

you can check in your calculator.

anyhow, to get the "recurring decimal to fraction", you start by setting to some variable, "x" in this case, then move the repeating part to the left of the point by multiplying it by some power of 10, and then do the equating.
3 0
3 years ago
Read 2 more answers
A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g. How many of each weight is needed?
Delicious77 [7]

The required number of weights used in chemical balance to weigh 237g is 4,1,1,7 respectively.

What is mathematical expression?

A mathematical expression expression in mathematical is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Here, it is given that :

A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g.

Now, let us find the number of weights for each weight type :

For 50g weight the maximum number of weights needed will be 4 that is :

50g x 4 = 200g

Now, for 20g weight the maximum number of weights needed will be 1 that is :

20g x 1 = 20g

Now, for 10g weight the maximum number of weights needed will be 1 that is :

10g x 1 = 10g

Now, for 1g weight the maximum number of weights needed will be 7 that is :

1g x 7 = 7g

Adding all the weights we get :

200g + 20g + 10g + 7g = 237g;

which is the required weight and the number of weights used is 4,1,1,7 respectively.

Read more about weights at:

brainly.com/question/16177712

#SPJ5

4 0
1 year ago
Read 2 more answers
Consider the 20 points of a 4×5 grid. You randomly choose two points from the 20 points. What is the probability that the two po
Serhud [2]

Answer:

The probability of both points falling in the same row or column is 7/19, or approximately 37%

Step-by-step explanation:

The easiest way to solve this is to think of it rephrased as "what is the probability that your second point will be in the same row or column as your first point".  With that frame of reference, you can simply consider how many other points are left that do or do not fall in line with the selected one.

After selecting one, there are 19 points left.

The row that the first one falls in will have 3 remaining empty points.

The column will have 4 remaining empty points.

Add those up and you have 7 possible points that meet the conditions being checked.

So the probability of both points falling in the same row or column is 7/19, or approximately 37%

6 0
3 years ago
2/3 times 3 times 2/7
fomenos

Answer:

4/7

Step-by-step explanation:

2/7 x 3= 6/7. 6/7× 2/3=4/7

7 0
3 years ago
Read 2 more answers
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