Mike discovered that the product of cellular respiration are the raw materials of Photosynthesis while the products of photosynthesis served as the raw materials for cellular respiration.
He also discovered that respiration is a catabolic process while photosynthesis is an anabolic process.
Another interesting fact seen by Mike is, the respiration releases energy while photosynthesis takes in energy.
Explanation:
- In the equation of cellular respiration , we can see that glucose and oxygen are utilized in the mitochondrion to produce carbon dioxide , water and chemical energy in the form of ATP.
- Glucose breaks down during cellular respiration .
- Again if we look at the chemical equation for photosynthesis in the chloroplast, we find that Carbon dioxide,which was produced during respiration is utilized along with water in presence of light energy to give out oxygen and Sugar (glucose)
C is your answer :)
And also C and D are true but its C.
This question is on Yahoo Answers
The answer is copper. Nonrenewable resources are those that cannot be readily/naturally replaced at rates that match those of consumption (an aspect that allow renewable resources to be sustainable). Copper are made deep in earth at very slow rates hence do not readily renew themselves. Organisms, on the other hand die, and are naturally replaced by offspring.
Carbon dioxide because people in other animals exhale carbon dioxide as a waste product. People and other animals need oxygen for plants produce oxygen during an important process called photosynthesis which turns the sun energy into nutrients so carbon dioxide would be the answer.
Answer:
F (pp) = 0.04
F (Pp) = 0.32
F (PP) = 0.64
Explanation:
Studying population genetics, we used the Hardy-Weinberg equilibrium model. In the case of snails, the H-W principle predicts that the total number of cases in the population should follow the following equation: PP + 2.Pp + pp = 200.
If a population has 200 snails and 8 are affected by a recessive condition, we have 4% affected, or 0.04.
This means that 0.04 corresponds to p², and p corresponds to 0.2.
Therefore, P is equal to 0.8 because p + P = 1.
Knowing the allele frequencies, we go to the frequency of the genotypes.
F (pp) = p² = 0.04 = 8 snails
F (Pp) = 2.Pp = 0.32 = 64 snails
F (PP) = P² = 0.64 = 128 snails
