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Blababa [14]
3 years ago
13

Simplify fully 125y2/10xy​

Mathematics
2 answers:
ch4aika [34]3 years ago
8 0

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Answer: 25y/2x

Explanation:

First you need to find the GCF of 125 and 10, which is 5

making it 25y^2/2xy, Then you get rid of 1 of the y's from both of the sides because you don't need them, they cancel eachother out, 25y/2x

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

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insens350 [35]3 years ago
4 0

Answer:

25y/2x

Step-by-step explanation:

125 y^2/10xy

25y/2x

5 two are  10 and  5 twentyfives are 125 so its 25/2 and one of y from y^2 in nuemantor got cancelled with y in denumentor...x remains

as is it

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Paladinen [302]

[Given]

{ x + y = 6

{ x = y + 4

[Plug-in our x value & solve]

[Given] x + y = 6

[ Plug-in] (y + 4) + y = 6

[Distribute] y + 4 + y = 6

[Combine like terms] 2y + 4 = 6

[Subtract 4 from both sides] 2y = 2

[Divide both sides by 2] y = 1

[Answer]

Third option - (5, 1)

-> You do not need to solve for x since this is the only option that has y = 1, but to solve for x we would do y + 4 = 1 + 4 = 5, so this answer fully checks correctly

Have a nice day!

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6 0
3 years ago
Alligator 1 initial weight is 4 lbs. the rate of growth is 2 lbs. per month. Alligator 2 initial weight is 8 lbs. the rate of gr
LekaFEV [45]

Answer:

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Step-by-step explanation:

Let the number of months be x

Alligator 1 weight = 4 + 2x

Alligator 2 weight = 8 + x

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The answer is 4 months

7 0
3 years ago
Solve for x show all work -2× + 5=4× -7​
Anestetic [448]
5=4x+2x-7
5+7=6x
12=6x
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6 0
4 years ago
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Dee Wallace's salary was $61,000 in 2006 and increased to $64,300 in 2009.
velikii [3]

Answer:

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Step-by-step Explanation:

Dee Wallace's salary in 2006 = $61,000 Dee Wallace's salary in 2009 = $64,300

The salary increased in => 2009 - 2006 = 3yrs

The amount of salary increased = 64,300-61000 = $3,300

The annual change of salary = 3,300/3 = $1,100

4 0
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Coefficient of x^2 in expansion of (x+2)^5
iVinArrow [24]
The x² term will be C(5,2)x²·2³ = 80x².

The coefficient is 80.

_____
C(n, k) = n!/(k!·(n-k)!)
C(5, 2) = 5·4/(2·1) = 10
8 0
3 years ago
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