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Ket [755]
3 years ago
7

Evaluate the indefinite integral. integar x4/1 + x^10 dx

Mathematics
1 answer:
ivann1987 [24]3 years ago
7 0

Answer:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c

Step-by-step explanation:

Given

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

Required

Integrate

We have:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

Let

u = x^5

Differentiate

\frac{du}{dx} = 5x^4

Make dx the subject

dx = \frac{du}{5x^4}

So, we have:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

\int\ {\frac{x^4}{1 + x^{10}}} \, \frac{du}{5x^4}

\frac{1}{5} \int\ {\frac{1}{1 + x^{10}}} \, du

Express x^(10) as x^(5*2)

\frac{1}{5} \int\ {\frac{1}{1 + x^{5*2}}} \, du

Rewrite as:

\frac{1}{5} \int\ {\frac{1}{1 + x^{5)^2}}} \, du

Recall that: u = x^5

\frac{1}{5} \int\ {\frac{1}{1 + u^2}}} \, du

Integrate

\frac{1}{5} * \arctan(u) + c

Substitute: u = x^5

\frac{1}{5} * \arctan(x^5) + c

Hence:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c

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