Answer:
The length of the diagonal HJ is 10.82 units
Step-by-step explanation:
* Lets revise the rule of the distance between two points
- 
, where
and 
are the two points
* Lets use this rule to find the length of the diagonal HJ
∵ The coordinates of point H are (-4 , 3)
∵ The coordinates of point J are (5 , -3)
∴ 
and 
∴ 
and 
- Lets find the length of the diagonal HJ by using the rule above
∴ HJ = 
∴ HJ = 
∴ HJ = 10.82
* The length of the diagonal HJ is 10.82 units
Answer:
200 - 200
-147 - 53
90 - 143
-229 - -86
86 - 0
Step-by-step explanation: im not sure on the last two but i tried?
Answer:
130° is the correct answer
∠QPR=80°
∠PQR+∠QPR+∠QRP=180°
∠PQR+∠QRP=100°
2(x+y)=100°
x+y=50°
So, in △QOR
x+y+∠QOR=180°
∴∠QOR=180°−50°
=130°
Answer:
14
Step-by-step explanation:
Answer:
A. The mean is increased by 3
Step-by-step explanation:
2 + 9 + 11 + 10 + 3 + 5 + 4 + 12 = 56/8 = 7
2 + 9 + 11 + 10 + 3 + 5 + 4 + 12 + 34 = 90/9 = 10
10 - 7 = 3
