1) Chemical reaction: CH₄ + H₂O → 3H₂ + CO ΔH = + 206 kJ/mol.
2) Chemical reaction: CO + H₂O → CO₂ + H₂, ΔH = + 2,8 kJ/mol.
3) Chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O ΔH = -802 kJ/mol.
4) Chemical reaction: 2H₂ + O₂ → 2H₂O ΔH = 2·(-242 kJ7mol) = - 484 kJ/mol.
Endothermic reaction (ΔH>o) and exothermic reaction (ΔH<span><0).</span>
The entropy of the given reactions increases (S° > 0):
- 2C2H6(g) + 7O2(g) ----> 4CO2(g) + 6H2O(g) ---> S° > 0.
- NH4Cl(s) ----> NH3(g) + HCl(g) ---> S° > 0.
<h3>What is entropy?</h3>
Entropy measure how disordered a system is. It a measure of how dispersed or random the total energy of a system is. The symbol for entropy is S.
A system in which entropy increases is one in which S° > 0.
The entropy of a system decreases when S° < 0.
Entropy of a system increases (S° > 0) if any change results in an increase in temperature, increase in number of molecules, or an increase in volume.
Considering the given systems, the entropy changes is as follows:
- 2C2H6(g) + 7O2(g) ----> 4CO2(g) + 6H2O(g) ---> S° > 0.
- 2CO2(g) + N2(g) ---->2CO(g) + 2NO(g) --> no change
- 2N2(g) + O2(g) -----> 2N2O(g) ---> decreases
- S (s,rhombic) + 2CO(g) ----> SO2(g) + 2C (s,graphite) ---> no change
- NH4Cl(s) ----> NH3(g) + HCl(g) ---> S° > 0.
In conclusion, an increase in volume and moles of substances results in entropy increase.
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I believe that the property referenced in 'like dissolves like" is polarity. Solvents are substances that dissolves solutes forming a solution. Solvents may be either polar or non polar; polar solvents contain bonds between atoms with very different electronegativities, such as oxygen and hydrogen, while non polar solvents have bonds between atoms with similar electronegativities such as hydrogen and carbon.
The volume of the flexible container that holds a sample of hydrogen gas at 153 kPa is 1.51L (option B).
<h3>How to calculate volume?</h3>
The volume of a substance can be calculated using the following formula:
P1V1 = P2V2
Where;
- P1 = initial pressure
- P2 = final pressure
- V1 = initial volume
- V2 = final volume
153 × 3 = 304 × V2
459 = 304V2
V2 = 459/304
V2 = 1.51L
Therefore, the volume of the flexible container that holds a sample of hydrogen gas at 153 kPa is 1.51L.
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Answer: kinetic energy
Explanation: searched it up
