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1 year ago

A 3.00 L flexible container holds a sample of hydrogen gas at 153 kPa.

Chemistry

1 answer:

Lisa [10]1 year ago

8 0

The volume of the flexible container that holds a sample of hydrogen gas at 153 kPa is 1.51L (option B).

<h3>How to calculate volume?</h3>

The volume of a substance can be calculated using the following formula:

P1V1 = P2V2

Where;

P1 = initial pressure
P2 = final pressure
V1 = initial volume
V2 = final volume

153 × 3 = 304 × V2

459 = 304V2

V2 = 459/304

V2 = 1.51L

Therefore, the volume of the flexible container that holds a sample of hydrogen gas at 153 kPa is 1.51L.

Learn more about volume at: brainly.com/question/2098026

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When 1.045 g of CaO is added to 50.0 mL of water at 25.0 °C in a calorimeter, the temperature of the water increases to 32.3 °C.

Rus_ich [418]

Answer:

1.71 kJ/mol

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

$\Delta H=m\times C\times \Delta T$

Where,

$\Delta H$ is the enthalpy change

m is the mass

C is the specific heat capacity

$\Delta T$ is the temperature change

Thus, given that:-

Mass of CaO = 1.045 g

Specific heat = 4.18 J/g°C

$\Delta T=32.3-25.0\ ^0C=7.3\ ^0C$

So,

$\Delta H=1.045\times 4.18\times 7.3\ J=31.88713\ J$

Also, 1 J = 0.001 kJ

So,

$\Delta H=0.03189\ kJ$

Also, Molar mass of CaO = 56.0774 g/mol

$Moles=\frac{Mass}{Molar\ mass}=\frac{1.045}{56.0774}\ mol=0.01863\ mol$

Thus, Enthalpy change in kJ/mol is:-

$\Delta H=\frac{0.03189}{0.01863}\ kJ/mol=1.71\ kJ/mol$

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2 years ago

Which volcanoes are located along colliding plate boundaries

puteri [66]

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2 years ago

What is the ph of a solution with [h3o+] = 1 × 10-9 m?

FrozenT [24]

PH scale is used to determine how acidic, basic or neutral a solution is
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2 years ago

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Vlad [161]

Answer:

We can solve this by the method of which i solved your one question earlier

so again here molar mass of C12H25NaSO4 is 288.372 and number of moles for 11900 gm of C12H25NaSO4 will be = 11900/288.372

which is almost = 41.26 moles

so to get one mole of C12H25NaSO4 we need one mole of C12H26O

so for 41.26 moles of C12H25NaSO4 it will require 41 26 moles of C12H26O

so the mass of C12H26O = 41.26× its molar mass

C12H26O = 41.26×186.34

= 7688.38 gm!!

so the conclusion is If you need 11900 g of C12H25NaSO4 (Sodium Lauryl Sulfate) you need C12H26O 7688.38 gm !!

Again i d k wether it's right or wrong but i tried my best hope it helped you!!

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2 years ago

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2 years ago