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dem82 [27]
3 years ago
9

When ch4(g) reacts with h2o(g) to form h2(g) and co(g), 206 kj of energy are absorbed for each mole of ch4(g) that reacts. write

a balanced thermochemical equation for the reaction with an energy term in kj as part of the equation. note that the answer box for the energy term is case sensitive. use the smallest integer coefficients possible and put the energy term in the last box on the appropriate side of the equation. if a box is not needed, leave it blank. + + + +?
Chemistry
1 answer:
jeka57 [31]3 years ago
7 0
1) Chemical reaction: CH₄ + H₂O → 3H₂ + CO ΔH = + 206 kJ/mol.
2) Chemical reaction: CO + H₂O → CO₂ + H₂, ΔH = + 2,8 kJ/mol.
3) Chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O ΔH = -802 kJ/mol.
4) Chemical reaction: 2H₂ + O₂ → 2H₂O ΔH = 2·(-242 kJ7mol) = - 484 kJ/mol.
Endothermic reaction (ΔH>o) and exothermic reaction (ΔH<span><0).</span>
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3 years ago
Un globo lleno de helio tenia un volumen de 8.5 L en el suelo a 20°C y a una presión de 750 torr. Cuando se le soltó, el globo s
Ray Of Light [21]

Answer:

El volumen del gas era 12.95 L

Explanation:

Se relaciona la presión y el volumen mediante la ley de Boyle, que dice:

“El volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión”

La ley de Boyle se expresa matemáticamente como:  P*V=k

Por otro lado, la Ley de Charles consiste en la relación que existe entre el volumen y la temperatura absoluta de una cierta cantidad de gas ideal, el cual se mantiene a una presión constante. Esta ley dice que cuando la cantidad de gas y de presión se mantienen constantes, el cociente que existe entre el volumen y la temperatura siempre tendrán el mismo valor:  

\frac{V}{T}=k

Por último, la Ley de Gay Lussac dice que la temperatura absoluta y la presión son directamente proporcionales. Es decir, cuando se mantiene todo lo demás constante, mientras suba la temperatura de un gas subirá también su presión. Y mientras la temperatura del gas baje, lo mismo ocurrirá con la presión:

\frac{P}{T}=k

Combinado las mencionadas tres leyes se obtiene:

\frac{P*V}{T} =k

Cuando se desean estudiar dos diferentes estados, uno inicial y una final de un gas, se puede aplicar:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

Recordando que la temperatura debe usarse en grados Kelvin, conoces los siguientes datos:

  • P1: 750 torr
  • V1: 8.5 L
  • T1: 20°C= 293°K (siendo 0°C=273°K)
  • P2: 425 torr
  • V2: ?
  • T2: -20°C= 253 °K

Reemplazando:

\frac{750 torr*8.5 L}{293K} =\frac{425 torr*V2}{253 K}

Resolviendo:

V2=\frac{750 torr*8.5 L}{293K} *\frac{253 K}{425 torr}

V2= 12.95 L

<u><em>El volumen del gas era 12.95 L</em></u>

<u><em></em></u>

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