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3 years ago

What is a host? Give two examples of ways humans serve as hosts for infectious diseases.

Chemistry

1 answer:

dlinn [17]3 years ago

6 0

Answer:

the direct transfer of bacteria,viruses or other germs for one person to another.

Explanation:

sometimes this happens an individual with the bacterium or virus touches.kisses.or cough or sneeze on someone who isn't infected

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What is the only letter not appearing on the periodic table?.

ivolga24 [154]

Answer:

The answer is j

Explanation:

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3 years ago

What is the H+ ion concentration of a solution with a pH of 7?

Ksivusya [100]

answer=H+]=10-7

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3 years ago

The path urine takes after it is formed until it leaves the body is the urethra, urinary bladder, and finally the ureter. True F

Vlad1618 [11]

Answer:

False

Explanation:

The urine is produced in the kidneys, each one of the kidneys is connected to a ureter. The ureter is a tube that propels the excreted urine to the urinary bladder. The urinary bladder is a deposit for the urine, here is collected and stored before disposal. After the urinary bladder, the urine goes through the urethra, which is a tube, to exit the body.

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3 years ago

How are elements usually found

riadik2000 [5.3K]

The answer is A cause gas clouds hold elements in it

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3 years ago

Read 2 more answers

The concentrated sulfuric acid we use in the laboratory is 98.0% sulfuric acid by weight. Calculate the molality and molarity of

timama [110]

Answer : The molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

Solution : Given,

Density of solution = $1.83g/cm^3=1.83g/ml$

Molar mass of sulfuric acid (solute) = 98.079 g/mole

98.0 % sulfuric acid by mass means that 98.0 gram of sulfuric acid is present in 100 g of solution.

Mass of sulfuric acid (solute) = 98.0 g

Mass of solution = 100 g

Mass of solvent = Mass of solution - Mass of solute = 100 - 98.0 = 2 g

First we have to calculate the volume of solution.

$\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}=\frac{100g}{1.83g/ml}=54.64ml$

Now we have to calculate the molarity of solution.

$Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}=\frac{98.0g\times 1000}{98.079g/mole\times 54.64ml}=18.29mole/L$

Now we have to calculate the molality of the solution.

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{98.0g\times 1000}{98.079g/mole\times 2g}=499.59mole/Kg$

Therefore, the molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

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3 years ago