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disa [49]
3 years ago
5

Solve the system of equations Y=2x+3. Y=x^2+3x+3

Mathematics
1 answer:
Setler79 [48]3 years ago
3 0

Answer:

x= -1

y= 1

Step-by-step explanation:

Set both equations equal to each other

2x+3=x^2+3x+3 then solve for x

2x=x^2+3x the 3 on either side cancel out

-x=x^2

-1=x

Then plug -1 in for one of the equations to solve for y

Y=2(-1)+3

Y=1

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Answer:

The minimum value of C is 20

Step-by-step explanation:

we have

2x+3y\geq 24 ----> constraint A

4x+y\geq 38 ----> constraint B

x\geq 0 ----> constraint C

y\geq 0 ----> constraint D

Using a graphing tool

The solution set of the constraints is the shaded area

see the attached figure

The vertices of the shaded area are (0,38),(9,2) and (12,0)

To determine the minimum value of C substitute the values of x and y of each vertex in the objective function and then compare the results

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For (0,38) ---> C=2(0)+38=38

For (9,2) ---> C=2(9)+2=20

For (12,0) ---> C=2(12)+0=24

therefore

The minimum value of C is 20

7 0
4 years ago
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navik [9.2K]

Answer:

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