Question

Three consecutive integers are such that three times the smallest is 26 more than the largest. Find the integers.

Answer 1

Answer: 14, 15 and 16

Step-by-step explanation:

Let the numbers be a, a+1 and a+2

We are told that the three consecutive integers are such that three times the smallest is 26 more than the largest. This can be formed into an equation as:

(3 × a) = (a+2 + 26)

3a = a + 28

3a - a = 28

2a = 28

a = 28/2

a = 14

The numbers are 14, 15 and 16