Perpendicular lines have slopes that are negative reciprocals of each other, that is, if one slope is a/b, the other slope is -b/a
the given line 3x-4y=24, 4y=3x-24, y=3/4x-6 has a slope of 3/4, so the slope of the perpendicular line has a slope of -4/3
y=(-4/3)x+b, b can be any number.
        
             
        
        
        
Answer:
-291
Step-by-step explanation:
4+(-5)(n-1)=4-5*59=4-295=291
 
        
             
        
        
        
3) x² - 121 = 0
x² = 121
x' = +√121
x' = 11
_______________
x'' = - √121
x'' = -11
Solution ⇒ S{-11 ; 11 } or (x-11)(x+11)
4) 4x² + 144 = 0
4x² = -144
x² = -144 / 4
x² = -36
x = √-36
No solution ⇒ S = ∅
5) z²+10z+21 = 0
Δ = 10² - 4(1)(21)
Δ = 100 - 84
Δ = 16
x' = (-10+4) / 2 = -6/2 = -3
x'' = (-10-4) / 2 = -14/2 = -7
Solution ⇒ S{ -7 ; -3} or (x+3)(x+7)
        
             
        
        
        
The other endpoint would have to be (-5,2), going off the definition of a midpoint. Since 3 is for units to the right of -1, that would mean that the other end point would have to be 4 units to the left, which is -5.
        
                    
             
        
        
        
Answer:

Step-by-step explanation:
This expression was kind of trial and error for me seeing as I'm not really good at logic, but this is pretty basic. There are three possible places the parentheses can be placed (assuming each pair holds 2 terms);
 
 
The answer to the first expression would be 45, which is not equal to 11.
The answer to the second expression would be 15, which is also not equal to 11.
The answer to the last expression is 11, so that is the correct answer.
Hope this helped :D
- Shay