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agasfer [191]
3 years ago
15

Since Beth was born, the population of her town has increased at a rate of 850 people per year. On Beth's 9th birthday, the tota

l population was nearly 307,650, Write and solve a linear equation to find the population on Beth's 16th birthday.
I only need the equation pls help

Edit: the equation needs to be in slope intercept form
Mathematics
1 answer:
scZoUnD [109]3 years ago
3 0

Answer:

editor edit

37,650

Step-by-step explanation:

37650

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What two integers have a sum of -7 and a product of -18?
Elis [28]

Answer:

-9 and 2

Step-by-step explanation:

-9 x 2

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3 years ago
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What is the solution to 6|3x+5| less than equal to 14?
zimovet [89]
In this case there will be 2 solutions to solve for in this equation, both will equal plus and minus the answer. Which is 14.

6(3x + 5) = +_ 14

The solutions will be the following :

(14/6 - 5)/3

(-14/6 - 5)/3.
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3 years ago
Fish is $20 a kilogram your recipe asks for 1/2 kilogram. How much will it cost
lora16 [44]

Known :

1 kg = $20

Asked :

½ kg = $...?

Answer :

1 kg = $20

½ kg = ½ × $20

= <u>$</u><u>1</u><u>0</u>

<em>Hope it helps and is useful</em><em> </em><em>:</em><em>)</em>

5 0
4 years ago
A cash box contains $74 made up of quarters, half-dollars, and one-dollar
Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

0.25q+0.50h+1.00d=74

\displaystyle{h=\frac{3}{5}d+1}

q=4(d+h)

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74

Next, substitute <em>h</em> in that equation with the expression from the second equation:

\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}

2d+0.9d+1.5=74\\2.9d+1.5=74

Solve for <em>d</em>, the number of one-dollar coins:

2.9d+1.5=74\\2.9d=72.5\\d=25

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{h=\frac{3}{5}(25)+1}

h=15+1\\h=16

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164

Then, verify that the coins total $74:

0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{16=\frac{3}{5}(25)+1}

16 = 15 + 1\\16 = 16\\\text{Check.}

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}

6 0
3 years ago
Solve the equation (z-5)/-7=11
Lorico [155]
Z = -72

Ask me in the comments section if you want the equation solved step-by-step.

Hope this helped!
4 0
3 years ago
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