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dem82 [27]
3 years ago
15

Help me I’m stuck and please can someone explain this to me

Mathematics
1 answer:
Degger [83]3 years ago
8 0

Answer:

84 degrees

Step-by-step explanation:

3x = 4x - 28. Reason: Alternate Exterior Angle are congruent

X=28 Reason: Algebra

Y+4x-28= 180 Reason: Straight angles = 180 degrees

Y=84. Reason: Algebra

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Can you guys pls help me out with both questions
masya89 [10]

3)

fixed cost =$ 99

variable cost per hour = $ 19

total cost can be given as

t = 99 + 19h

where h is number of hours vehicle used.

4) weekend daily cost is $ 29.99

total day she rented = friday + saturday + sunday = 3 days

so total rent = 29.99 × 3 = $ 89.97

4 0
3 years ago
How do you calculate net income on an income statement?
Novosadov [1.4K]
Most income statements have the net income on them but if they don't you subtract all the expenses like taxes, medical insurances, etc. from the gross income and you will have the net income.
4 0
3 years ago
Which equation describe a line that has a slope of 3 and passes through the point (2,3)?
kogti [31]
It should be: y=3x-3

7 0
4 years ago
Read 2 more answers
Graph the following set of parametric equations on your calculator and select the matching graph.
Anettt [7]

Answer:

Graph 2

Step-by-step explanation:

The equation x = t² - 3 is represented by exponential growth, ( t² ) so it's graph will be similar to the first graph, graph 1, in our options. Then again we have to consider the equation y = √t - 2, which will be similar to graph 4, but with a greater slope. This leaves us with a solution of graph b.

3 0
4 years ago
A box in a supply room contains 24 compact fluorescent lightbulbs, of which 8 are rated 13-watt, 9 are rated 18-watt, and 7 are
Marrrta [24]

Answer:

a) There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

b) There is a 8.65% probability that all three of the bulbs have the same rating.

c) There is a 12.45% probability that one bulb of each type is selected.

Step-by-step explanation:

There are 24 compact fluorescent lightbulbs in the box, of which:

8 are rated 13-watt

9 are rated 18-watt

7 are rated 23-watt

(a) What is the probability that exactly two of the selected bulbs are rated 23-watt?

There are 7 rated 23-watt among 23. There are no replacements(so the denominators in the multiplication decrease). Then can be chosen in different orders, so we have to permutate.

It is a permutation of 3(bulbs selected) with 2(23-watt) and 1(13 or 18 watt) repetitions. So

P = p^{3}_{2,1}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = \frac{3!}{2!1!}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 3*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 0.1764

There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

(b) What is the probability that all three of the bulbs have the same rating?

P = P_{1} + P_{2} + P_{3}

P_{1} is the probability that all three of them are 13-watt. So:

P_{1} = \frac{8}{24}*\frac{7}{23}*\frac{6}{22} = 0.0277

P_{2} is the probability that all three of them are 18-watt. So:

P_{2} = \frac{9}{24}*\frac{8}{23}*\frac{7}{22} = 0.0415

P_{3} is the probability that all three of them are 23-watt. So:

P_{3} = \frac{7}{24}*\frac{6}{23}*\frac{5}{22} = 0.0173

P = P_{1} + P_{2} + P_{3} = 0.0277 + 0.0415 + 0.0173 = 0.0865

There is a 8.65% probability that all three of the bulbs have the same rating.

(c) What is the probability that one bulb of each type is selected?

We have to permutate, permutation of 3(bulbs), with (1,1,1) repetitions(one for each type). So

P = p^{3}_{1,1,1}*\frac{8}{24}*\frac{9}{23}*\frac{7}{22} = 3**\frac{8}{24}*\frac{9}{23}*\frac{7}{22} = 0.1245

There is a 12.45% probability that one bulb of each type is selected.

3 0
3 years ago
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