Since ∠1 and ∠2 are complementary...they add up to be 90°.
∠1 = (-2x + 54)
∠2 = (8x + 18) we add these two up
6x + 72 = 90 subtract 72 from both sides
6x = 18
x = 3 place the value of x into the ∠2 equation
(8x + 18) = 8(3) + 18 = 24 + 18 = ∠2 = 42°
See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer isjn=16
Answer:
or 15.231546
Step-by-step explanation: